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If two white sheep produce a black offspring the parent's genotypes for colr must be?
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What is the genotype of the offspring that do not share the parents phenotype?
Genotype is the coded for traitPhenotype is the visible characteristicSo in the case where both parents had heterozygous dominant Brown eyes (Bb - big B for brown, dominant gene; little b for blue recessive gene); it is possible for the child to have blue eyes, by being homozygous recessive (bb).However this is an educated guess, as your question does not make sense.
When doing a genetic cross why is it necessary to remove the parent flies before the pupae have hatched?
Usually, the parent flies will have a different genotype to the F1 generation (their offspring). For example, if the parents had WW (black eyes) and ww (white eyes), their offspring would all have Ww (black eyes). If you were experimenting further, you would want the F1 generation to cross - with Ww X Ww. If you did not remove the parental generation, you could have crosses between them and the F1 generation, which would result in different genotypes. If the parents were not removed, you could have the following crosses: Ww X WW Ww X ww WW X ww Ww X Ww The only cross that you would desire in the experiment would be F1 X F1 (Ww X Ww), which would give you the desired genotypes for the F2 generation.
What are the genotypes of the parental dogs one is black the other is brown who have ONLY black or yellow puppies. Explain how you determined their genotypes.?
BBEe and bbEe. Black is dominant, and brown is recessive. Yellow is also recessive. Because one parent is brown, for none of the puppies to also be brown the black parent cannot carry the recessive allele on the B locus. Because neither parent is yellow but some of the puppies are, both parents must carry the recessive allele on the E locus.
What two genotypes are possible for a dog that has black fur?
No. They might have the same phenotype, but would not have the same genotype.
Why are Punnett squares useful in genetics?
You have a square the is split into fourths. 2 and 2 in bottom. It looks like a window. On top of the two top squares you put the alleles of the first parent. On the left you put the to alleles of the other parent. And you basically get one allele from each parent and put it in the square and it gives you the probably outcomes of the offspring.
To Is to produce offspring that are similar to the parents?
Its called budding.
In cocker spaniels black coat color is dominat to red Two black cockers have eight puppies 5 black and 3 red What are the genotypes of the parents?
The parents genotypes will be Black and Red. BLACK being the dominant and red the recessive. The puppies genotypes would be Black and red, Black and Black, red and red.
What was the genotype of the offspring the did not share the parents' phenotype?
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
What was the phenotype of the offspring that did not share of the parents phenotype?
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
What is the probability of two black guinea pigs having black offspring?
depends on the two guinea pigs genotypes. could be anywhere from 75 to 100 percent.
In certain rats black fur is dominant over white fur If two rats both heterozygous for fur color are mated their offspring would be expected to have?
There different genotypes and two different colors Black fur is dominant --> F White fur is recessive --> f The parents are bot Ff (heterozygotes, and because black fur is dominant they have a black fur). If they mate, you get parents: Ff x Ff Offspring: FF Ff Ff ff so 25% will be homozygous for Black fur 2x25=50% will be heterozygous, and have a Black fur and 25% wil be homozygous for White fur. Hence, of their offspring, 75% will have a black fur and 25% will have a white fur
A female quinea pig homozygous dominant for black fur color is mated with a male homozygous for white fur In a litter of eight offspring there would probably be?
To answer this, first determine the genotypes of the parents. The female is homozygous dominant, which means it carries two copies of the black allele (which we will designate B), so its genotype we can represent as BB. The male is homozygous for the recessive trait (white, designated as b), so its genotype can be represented as bb. So the cross looks like this: BB X bb Next, we must determine the types of gametes each parent can produce. In this case it's easy, because both are homozygous. The female can only produce B gametes, while the male can only produce b gametes. Since the offspring carry one allele from each parent, all of the offspring can have only one genotype: Bb. Since black (B) is the dominant allele, and every offspring carries the dominant allele, all eight of the offspring from this cross will be black.
What will a black and a ruby eyed white gerbil produce?
Well, it depens what color the parents are and well if the black gerbil has black parents and if the ruby eyed white gerbils parents are white there babies will probably produce white and black babies.
Can two black-coated guinea pigs produce an offspring with a whit coat?
Yes
What is the genotype of the offspring that do not share the parents phenotype?
Genotype is the coded for traitPhenotype is the visible characteristicSo in the case where both parents had heterozygous dominant Brown eyes (Bb - big B for brown, dominant gene; little b for blue recessive gene); it is possible for the child to have blue eyes, by being homozygous recessive (bb).However this is an educated guess, as your question does not make sense.
If a homozygous black guinea pig is crossed with a white guinea pig what is the probability that an offspring will have black fur?
depends if the black fur gene is dominant.. if it is... then yu would cross BB with bb making all heterozygous genotypes(Bb) therefore, having all possible offspring with black fur so theres a 100% probability of offspring with black fur(:
What is the difference between a pure line and a inbred?
A pure line (pure breed) refers to a group of individuals that consistently breed to produce a certain characteristic - and have the same genetic makeup (for those characteristics). For example, Guinea pigs with BB will produce offspring with black fur, these are purebred. However, Guinea pigs with Bb are not purebred (as they could have offspring with black or white fur). Inbred individuals have parents that are closely related, such as brother/sister, or cousins.
