0
A female quinea pig homozygous dominant for black fur color is mated with a male homozygous for white fur In a litter of eight offspring there would probably be?
To answer this, first determine the genotypes of the parents. The female is homozygous dominant, which means it carries two copies of the black allele (which we will designate B), so its genotype we can represent as BB. The male is homozygous for the recessive trait (white, designated as b), so its genotype can be represented as bb. So the cross looks like this: BB X bb Next, we must determine the types of gametes each parent can produce. In this case it's easy, because both are homozygous. The female can only produce B gametes, while the male can only produce b gametes. Since the offspring carry one allele from each parent, all of the offspring can have only one genotype: Bb. Since black (B) is the dominant allele, and every offspring carries the dominant allele, all eight of the offspring from this cross will be black.
What else can I help you with?
If the male parent has the genotype AAA and the female parent has the genotype AAA offsprings genotype will be?
The offspring's genotype will be AA. Both parents are homozygous dominant, AA, having only dominant alleles to pass on to their offspring. So each parent can pass on only the dominant allele (A) to its offspring. So the offspring will also be homozygous dominant, AA.
What does it mean if a plant is true breeding?
Mendel started out with plants that "bred true". That is, when tall plants were self-pollinated (or cross-pollinated with others like them), plants in following generations were all tall; when the short plants were self-pollinated (or cross- pollinated with others like them) the plants in following generations were all short.
How many dominant alleles are required in a genotype to show the dominant phenotype?
If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait) If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait)
If a female fruit fly heterozygous for red eyes crossed with a white eyed male what percent of their offspring would have white eyes?
All the offspring will have red eyes because the trait for red eyes is dominant and the female is heterozygous (carrying one dominant red eye allele). White eyes are recessive, so the offspring would need to inherit two white eye alleles to have white eyes.
What is a X linked carrier homozygous?
An X linked carrier is one who carries a mutation in a gene found on the X sex chromosome. A carrier of the trait doesn't display phenotypic symptoms of the disease or mutation but can transfer the mutation in that gene to their offspring (ex: the carrier of a premutation that when transferred to the offspring via the X chromosome will cause the full mutation associated with that gene). A person could be a homozygous carrier if for instance, she were female (two X chromosomes) and carried the premutation associated with the disease. Some diseases need both alleles of the gene to be mutated. If only one allele is mutated (heterozygote) that person may be a carrier for that mutation and can thus pass on that mutation to their children.
What is the ratios for a heterorozygous female and a homozygous dominant male?
The offspring will inherit one dominant allele from the homozygous dominant male and have a 50% chance of inheriting the dominant allele from the heterozygous female. Therefore, the ratio of offspring with the dominant allele to those without will be 1:1.
What is the genotype and phenotype ratios for a homozygous dominant female and a homozygous resessive male?
When a homozygous dominant female (genotype AA) is crossed with a homozygous recessive male (genotype aa), all offspring will inherit one dominant allele from the mother and one recessive allele from the father, resulting in a genotype of Aa for all offspring. The phenotype ratio will show all offspring displaying the dominant trait. Thus, the genotype ratio is 100% Aa, and the phenotype ratio is 100% expressing the dominant trait.
If the male parent has the genotype AAA and the female parent has the genotype AAA offsprings genotype will be?
The offspring's genotype will be AA. Both parents are homozygous dominant, AA, having only dominant alleles to pass on to their offspring. So each parent can pass on only the dominant allele (A) to its offspring. So the offspring will also be homozygous dominant, AA.
Which gender can have white eyes if the female parent is homozygous dominant for red eyes and if the male parent has white eyes?
The offspring will have red eyes because the mother is homozygous dominant for red eye color. White eye color is a recessive trait and can only be expressed when both parents pass on the white allele. Since the father has white eyes, the male offspring will inherit the white eye color.
When a male pig from a line of true-breeding (homozygous) black solid-hooved pigs was crossed to a female from a breed (homozygous) of red cloven-hooved pigs their several progeny all looked alike?
The progeny of the cross between the homozygous black solid-hooved male pig and the homozygous red cloven-hooved female pig all looked alike due to the principle of dominance in genetics. The black solid-hooved trait is likely dominant over the red cloven-hooved trait, resulting in all offspring displaying the black solid-hooved phenotype. Since both parents are homozygous, all offspring inherit the dominant allele from the black parent, leading to uniformity in appearance.
Which gender can have white eyes if the female parent is homozygous dominant for red eyes and the male parent has white eyes?
Male
What is the approximate probably that human offspring will be female?
50 percent
Why can the father not be homozygous for a dominant trait?
Homozygousity is defined as having the two alleles that are the same for a certain locus. For example, AA or AA are both homozygous. Dominance, however, is a different concept and it is independent of homozygousity. In addition, both dominance and homozygousity are independent of the sex of the individual (unless the trait is X-linked) Therefore, the three possibilities of homozygous dominant, heterozygous, and homozygous recessive for a trait are available for a male just as a female individual.
What does it mean if a plant is true breeding?
Mendel started out with plants that "bred true". That is, when tall plants were self-pollinated (or cross-pollinated with others like them), plants in following generations were all tall; when the short plants were self-pollinated (or cross- pollinated with others like them) the plants in following generations were all short.
How many dominant alleles are required in a genotype to show the dominant phenotype?
If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait) If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait)
If a female fruit fly heterozygous for red eyes crossed with a white eyed male what percent of their offspring would have white eyes?
All the offspring will have red eyes because the trait for red eyes is dominant and the female is heterozygous (carrying one dominant red eye allele). White eyes are recessive, so the offspring would need to inherit two white eye alleles to have white eyes.
What offspring would result from a cross of a homozygous red-eyed female fruit fly and a vermilion-eyed male fruit fly?
All offspring would have red eyes because the gene for red eyes is dominant over the gene for vermilion eyes. The offspring would all be heterozygous for eye color, inheriting one red-eyed allele from the female and one vermilion-eyed allele from the male.
