To answer this, first determine the genotypes of the parents. The female is homozygous dominant, which means it carries two copies of the black allele (which we will designate B), so its genotype we can represent as BB. The male is homozygous for the recessive trait (white, designated as b), so its genotype can be represented as bb. So the cross looks like this: BB X bb Next, we must determine the types of gametes each parent can produce. In this case it's easy, because both are homozygous. The female can only produce B gametes, while the male can only produce b gametes. Since the offspring carry one allele from each parent, all of the offspring can have only one genotype: Bb. Since black (B) is the dominant allele, and every offspring carries the dominant allele, all eight of the offspring from this cross will be black.
4 black and 4 white
The offspring's genotype will be AA. Both parents are homozygous dominant, AA, having only dominant alleles to pass on to their offspring. So each parent can pass on only the dominant allele (A) to its offspring. So the offspring will also be homozygous dominant, AA.
If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait) If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait)
Mendel started out with plants that "bred true". That is, when tall plants were self-pollinated (or cross-pollinated with others like them), plants in following generations were all tall; when the short plants were self-pollinated (or cross- pollinated with others like them) the plants in following generations were all short.
They are result of a cross among F 1 .
Coffin-Lowry syndrome is an x-linked dominant condition which means it can only be passed on by a female. There are no known instances of a man passing CLS on to offspring. If the mother has CLS or is a CLS carrier, then there is a 50/50 chance of passing on the condition to her offspring. CLS can also occur as a spontaneous mutation, where there is no family history of the condition.
The offspring's genotype will be AA. Both parents are homozygous dominant, AA, having only dominant alleles to pass on to their offspring. So each parent can pass on only the dominant allele (A) to its offspring. So the offspring will also be homozygous dominant, AA.
Male
Male
50 percent
Homozygousity is defined as having the two alleles that are the same for a certain locus. For example, AA or AA are both homozygous. Dominance, however, is a different concept and it is independent of homozygousity. In addition, both dominance and homozygousity are independent of the sex of the individual (unless the trait is X-linked) Therefore, the three possibilities of homozygous dominant, heterozygous, and homozygous recessive for a trait are available for a male just as a female individual.
If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait) If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait)
Mendel started out with plants that "bred true". That is, when tall plants were self-pollinated (or cross-pollinated with others like them), plants in following generations were all tall; when the short plants were self-pollinated (or cross- pollinated with others like them) the plants in following generations were all short.
The probable genotype for the white mouse would be homozygous recessive.
If red eyes are dominant, then 75% will have red eyes and 25% will have white eyes. The genetic breakdown is: 25% will be RR (homozygous red eyes), 50% will be Rr (heterozygous red eyes) and 25% will be rr (homozygous white eyes).
Male and female genes combine to determine different traits of the offspring. The dominant gene is another term for the stronger gene.
They are result of a cross among F 1 .
The combination of a female offspring would be XX