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When Morgan mated a white-eyed male fruit fly with a red-eyed female fruit fly, the first generation offspring all had red eyes. In the next generation, because females would have the X chromosome for white eyes, about half the offspring would have white eyes. The offspring with white eyes were all male, meaning he discovered eye color in fruit flies showed a sex-linked trait.

The result of this was a generation of red eyed and white eyed individuals. If the red eyed female was heterozygous, this is possible.

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Related Questions

What is the ratios for a heterorozygous female and a homozygous dominant male?

The offspring will inherit one dominant allele from the homozygous dominant male and have a 50% chance of inheriting the dominant allele from the heterozygous female. Therefore, the ratio of offspring with the dominant allele to those without will be 1:1.


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When a homozygous dominant female (genotype AA) is crossed with a homozygous recessive male (genotype aa), all offspring will inherit one dominant allele from the mother and one recessive allele from the father, resulting in a genotype of Aa for all offspring. The phenotype ratio will show all offspring displaying the dominant trait. Thus, the genotype ratio is 100% Aa, and the phenotype ratio is 100% expressing the dominant trait.


If the male parent has the genotype AAA and the female parent has the genotype AAA offsprings genotype will be?

The offspring's genotype will be AA. Both parents are homozygous dominant, AA, having only dominant alleles to pass on to their offspring. So each parent can pass on only the dominant allele (A) to its offspring. So the offspring will also be homozygous dominant, AA.


A female quinea pig homozygous dominant for black fur color is mated with a male homozygous for white fur In a litter of eight offspring there would probably be?

To answer this, first determine the genotypes of the parents. The female is homozygous dominant, which means it carries two copies of the black allele (which we will designate B), so its genotype we can represent as BB. The male is homozygous for the recessive trait (white, designated as b), so its genotype can be represented as bb. So the cross looks like this: BB X bb Next, we must determine the types of gametes each parent can produce. In this case it's easy, because both are homozygous. The female can only produce B gametes, while the male can only produce b gametes. Since the offspring carry one allele from each parent, all of the offspring can have only one genotype: Bb. Since black (B) is the dominant allele, and every offspring carries the dominant allele, all eight of the offspring from this cross will be black.


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The combination of a female offspring would be XX


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Female offspring are commonly referred to as daughters.


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The offspring will have red eyes because the mother is homozygous dominant for red eye color. White eye color is a recessive trait and can only be expressed when both parents pass on the white allele. Since the father has white eyes, the male offspring will inherit the white eye color.


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50% of the offspring are female. Gender determination in offspring is typically governed by a 50/50 chance.


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A young bovine that has not had an offspring is called a heifer.


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An X linked carrier is one who carries a mutation in a gene found on the X sex chromosome. A carrier of the trait doesn't display phenotypic symptoms of the disease or mutation but can transfer the mutation in that gene to their offspring (ex: the carrier of a premutation that when transferred to the offspring via the X chromosome will cause the full mutation associated with that gene). A person could be a homozygous carrier if for instance, she were female (two X chromosomes) and carried the premutation associated with the disease. Some diseases need both alleles of the gene to be mutated. If only one allele is mutated (heterozygote) that person may be a carrier for that mutation and can thus pass on that mutation to their children.