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If you multiply the voltage in a circuit by the current what are you going to get for your answer?
Wiki User
∙ 15y ago
Voltage x current = power (watts)
Wiki User
∙ 15y ago
Wiki User
∙ 16y agoPower
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How are current and voltage related in a circuit?
Actually, they are not related. They are two separate components. To illustrate: take a waterfall for example. The current (amperage) flowing over the waterfall is the current or amperage (how much water is going over the waterfall. The Voltage is, essentially, the potential energy available. If the water fall is 100 feet tall it will have significantly more "voltage" than if it is only one inch tall. A 100 foot high water fall that has only one drop of water per second going over it will have a high "voltage" but a very low current. A one inch waterfall have 300,000 gallons per second going over it will have a very high "current" but low voltage. So concerning an electrical circuit, if one of the current or voltage are low enough it will not harm you regardless of how high the other one is. Volts and amperage together basically combined in a formula to determine the number of watts, but they are not specifically related to each other. As per Ohm's law V=IR where V is voltage, I is current and R is resistance. since Voltages is equal to current times resistance than makes them directly proportional to each other and therefor related.
Why does a circuit stop working when you remove the battery?
The battery is the power source of the circuit. It supplies current to the circuit and the circuit is simply a path for the current to follow. When you remove the current (battery), the path still exists but there is no current going through it.
What do parallel circuit NOT have in common with series circuit?
A parallel circuit is different in many ways from a series circuit: 1. In parallel, the voltage across all the devices connected is the same. 2. If a fault occurs in any device connected in parallel combo, then it has no effect on the operation of the other device. 3. In series circuit the current flowing through all the devices is the same while in case of the parallel one the voltage across all the devices is same.
What does kirchoff's law state?
Kirchhoffs Laws are statements about circuits. There are two laws ; 1) The total current entering any point in a closed circuit equals the total current leaving that point. 2) The sum of the voltage changes around any closed path is zero. These "Laws" are a consequence of the more fundamental laws of conservation of charge and conservation of energy.
What does an ameter do in a circuit?
An Ammeter provides a visual display of the magnitude of the current flowing through it. Ideally, the ammeter does nothing "in the circuit". You don't want your test equipment to change anything going on in the circuit you're measuring.
State two rules for the voltage and current in a series circuit?
Kirchoff's voltage law and Kirchoff's current law
What happens to the voltage if the current increases?
Yes, if the resistance remains constant. Power is voltage times current, and current is voltage divided by resistance, so power is voltage squared divided by resistance. In essence, the power increases as the square of the voltage.
What will increase the voltage in a circuit?
There is a way to use capacitors to increase the voltage in an ac circuit. It increases it by about 50 %. It was used to increase the voltage going to motors. It is seldom used now that it is much easier to run a higher voltage line into a place of business. It does not work for Direct Current.
What is the measured voltage across the 680 ohms resistor?
No one is going to be able to tell you that. You are looking for the measured voltage, so go and measure it. In any case, if you were just looking for the voltage it will depend on the circuit current. You can work it out using ohms law (Voltage = Current * Resistance).
What is the behavior of current and voltage in a series cricuit?
Kirchhoff's Current Law: The sum of the signed currents entering a node is zero. A consequence of this is that, in a series circuit every node only has two connections, one entering and one leaving, thus, in a series circuit, the current is the same at every point. Kirchhoff's Voltage Law: The sum of the signed voltage rises going around a series circuit is zero. This means, for example, that if you have two voltage drops, such as two bulbs in series with a battery, the voltage drops across them will add up to the voltage across the battery.
How many degrees are the current and voltage out of phase with each other in a pure resistive circuit?
The voltage and current sine waves cross the zero line at the same time and going in the same direction. The phase angle is 0°. They are said to be in-phase.
Does the current in a pure capacitive circuit lead or lag the applied voltage?
Answer #1Just remember our friend ELI the ICE man! E is voltage, I is current, L is inductance, and C is capacitance. ELI In an inductively reactive circuit (L), the voltage (E) comes first, then the current (I) lags behind. ICE In a capacitively reactive circuit (C), the current (I) leads, then the voltage (E) comes later. Note that while your assumption (in the stated question) is correct, an engineer or electrician would not say it that way. The voltage waveform is the constant, and the current waveform is said to lead or lag. This is because reactive or non-linear loads distort the current. If you look at a power-factor meter, and it says leading or lagging, it is referring to the current. It would be more accurate to re-phrase your question: In a capacitive reactive circuit does the current lead the voltage? Yes! Answer #2: Another method I learned from one of my EE professor is that in an inductor the current lags the voltage because the electrons get dizzy going through all of those loops (coils) in the inductor and "lag" behind the voltage.
Why kirchhoff's voltage law is applicable for open circuit?
Kirchoff's Voltage Law does not work, per se, for open circuits. You need a closed circuit for it to make any kind of sense.The signed sum of the voltage drops going around a series circuit is equal to zero.That means you have a closed circuit.However, it can be argued, correctly, that an open circuit is simply one that has two nodes with infinite resistance between them. Assuming that all of the other nodes have something less than infinite resistance between them, then Kirchoff's law does work, of sorts, in that the voltage drop across all nodes that are not voltage sources will be zero, because there is no current, and the voltage drop across the two nodes with infinite resistance will be equal to the sum of the voltage rises across the voltage sources. Current sources in such a circuit will not work, because, with zero current, they would attempt to generate infinite voltage.AnswerKirchhoff's Voltage Law does indeed apply to an open circuit, because the voltage drop across the open part of the circuit is numerically equal to the supply voltage and, hence, the algebraic sum of the voltage drops around that particular loop is zero.Kirchoff's Voltage Law does not work, per se, for open circuits. You need a closed circuit for it to make any kind of sense.The signed sum of the voltage drops going around a series circuit is equal to zero.That means you have a closed circuit.However, it can be argued, correctly, that an open circuit is simply one that has two nodes with infinite resistance between them. Assuming that all of the other nodes have something less than infinite resistance between them, then Kirchoff's law does work, of sorts, in that the voltage drop across all nodes that are not voltage sources will be zero, because there is no current, and the voltage drop across the two nodes with infinite resistance will be equal to the sum of the voltage rises across the voltage sources. Current sources in such a circuit will not work, because, with zero current, they would attempt to generate infinite voltage.Read more: http://wiki.answers.com/Why_kirchhoff's_voltage_law_is_applicable_for_open_circuit#ixzz1i2fWNqfN
Energy input remains constant and voltage remains the same in a circuit but current decreases why?
Power is voltage times current. If power and voltage remains the same, then current cannot decrease - it must also remain the same.The only viable explanation, assuming the question is valid, is that there is a parallel circuit, and one resistance increases while the other decreases, keeping the net resistance the same, but shifting the power from one branch to the other.Another answerNormally, if the voltage remains the same and the current decreases in a particular circuit, then the resistance of that circuit must be increasing and the total energy input must also reduce.If the total energy input remains constant (and yet the voltage remains the same) then some of the current being supplied by the source - and therefore also some of the energy - must be going to some other place outside the circuit in question, e.g. there could now be a ground fault...
Can you compare kirchhoff's law to ohm's law?
No. They say different things. Ohm's Law says that voltage is resistance times current. Kirchoff's Voltage Law says that the signed sum of the voltage drops going around a series circuit is zero. A consequence of this is that two elements in parallel with each other have the same voltage across them. Kirchoff's Current Law says that the signed sum of the currents entering a node is zero. A consequence of this is that the current at every point in a series circuit is the same.
What happens to the current when more resistors are added in series?
Current decreasesWhen voltage remains constant and resistance increases the current in the circuit will reduce.More informationV=IRwhere V is voltage,I is current andR is resistance.From the above equation,R=V/I, and hence resistance is indirectly proportional to current.Therefore, an increase in resistance would have the effect of decreased current.NB: this holds true only as long as the voltage remains constant.Another opinionHowever, this is only true in the case of a circuit connected in series.When circuits are connected in parallel, the opposite happens. If there is an increase in the amount of resistors in parallel, the total resistance of the circuit then decreases and the current increases subsequently.Yet another viewNo, that's not stated right.If more resistors are added in parallel - so that the circuit's overall total resistance decreases and its total current increases - that is NOT in any way the opposite of what this question is asking about...Let's make this crystal clear, so that there is no confusion: "an increase in the amount of resistors" is NOT the same as "an increase in resistance".So a parallel circuit behaves EXACTLY the same as a series circuit: if its overall resistance increases, the overall current going through the parallel circuit decreases AND if its overall resistance decreases, the overall current going through the parallel circuit increases.Actually, the second opinion is correctIn a parallel circuit, there are more branches to allow electrons back to the power supply, so current increases. With more resistors in a circuit, the overall resistance in a parallel circuit DECREASES.In a series circuit, current is the same throughout. So if more resistors are added, resistance INCREASES and so current DECREASES.
What is the voltage across a closed circuit if R equals 700KΩ and you equals 5 A?
First, a closed circuit would not have any voltage across the circuit. As going around the whole circuit, the sum of the voltage drops equals zero. However, you can measure the voltage drop across this particular part of the circuit (a 700 kΩresistor - probably a spark gap or insulation that broke down and arced through).Use Ohm's Law: V = IR (voltage = current times resistance). Note that in normal circuits, you won't have such a high current combined with such a high resistance (the power dissipation in this case would be 17.5 MW!) Perhaps the current was supposed to be in milli-ampere instead of ampere. Anyway for the 700 kiloohm resistance it is 3,500,000 Volts (3.5 Megavolts)
