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Ohms law is: R= V x I (resistance = voltage / current) ...where an led typically likes 20mA (0.02A) of current running through it and 2V of voltage across it, therefore:

R= V x I = (220-2) / 0.02 = 218 / 0.02 = 10,900 ohms = 10.6kohms (10kohms will do fine).

hope that helps

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Q: If you will put an LED in a series with resistor in 220 volts what is the resistance of resistor?
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