The answer is six.
Expected based on probability.
This would be because phenotypes are the observable characteristics whilst genotypes are the actual genes. If we are given the genes: R (dominant) and r (recessive), and 2 organisms with Rr genes (one dominant and one recessive) produce offspring, their offspring will have one of the following genes, with the percentage chance in brackets: RR (25%) Rr (50%) rr (25%) However, you can't detect recessive genes if a dominant gene is present, thus there will be no observable difference between the RR and Rr organism, besides for their offspring. Thus, the phenotype is 75% and 25%, unlike for the genotype.
crossing over
This would result in 1 heterozygous offspring. You can think of it like this: If the first parent is homozygous it would have AA alleles, the second heterozygous parent would be AB. When they mix genetically it would result in 4 combinations: AA, AA, AA, AB. As there is only one B there can only be one heterozygous offspring. This is not expected it is certain.
50%
Mendel Diagrams. If the offspring gets a dominate gene from both parents, the offspring will exhibit traits from the dominate gene. If the offspring gets a dominate gene from one parent and a recessive gene from another, the offspring will exhibit traits from the dominate gene. If the offspring get a recessive gene from both parents, the offspring will exhibit traits from the recessive gene.
Fyugugy
25%
Expected based on probability.
Let T=trait (dominant) Let t= trait (recessive) Father has Tt and mother also has Tt The possible combinations for offspring are: TT Tt Tt and tt Therefore There is a 3/4 change of the offspring having the dominant trait and a 1/4 Chance of the offspring having the recessive trait It should also be noted that there is a 1/4 chance of the offspring carrying two dominant genes meaning that any of their children will also share the dominant trait
This would be because phenotypes are the observable characteristics whilst genotypes are the actual genes. If we are given the genes: R (dominant) and r (recessive), and 2 organisms with Rr genes (one dominant and one recessive) produce offspring, their offspring will have one of the following genes, with the percentage chance in brackets: RR (25%) Rr (50%) rr (25%) However, you can't detect recessive genes if a dominant gene is present, thus there will be no observable difference between the RR and Rr organism, besides for their offspring. Thus, the phenotype is 75% and 25%, unlike for the genotype.
your mom, your dad
i got the same question on my test its 1/4 recessive :)
If the lethal gene is recessive, and the parent carrying it is heterozygous for that gene, it can be passed down to offspring in the recessive form. If the mate of the parent happens to be carrying the same gene heterozygously, 50% of offspring will be expected to inherit the recessive lethal gene heterozygously. 25% of the offspring will be expected to inherit the lethal gene homozygously, leading to death. The remaining 25% of offspring we will expect to homozygously inherit the non-lethal gene. 1:2:1 ratio
0.25
3
50 percent