Assuming that the voltage between two nodes are the same, current changes with branches. If you add branches, this means the current will be divided, depending on the resistance strength. Greater the resistance, the lower the current. If there is no resistance, it will end up in a short circuit, getting all the current. If there is great resistance, there will be very little current passing.
Mathematically, V=I*R is the formula. If you know the voltage between two nodes, you can calculate the currency (I) in each branch and for the whole nodes by putting in the particular resistance value for the branch or the whole nodes.
The sum of the branch currents will equal the supply current. Or, to put it another way (in terms of Kirchhoff's Current Law), the sum of the currents approaching a junction must equal the sum of the currents leaving that junction.
-- In a series circuit, no matter where you install the ammeter, it will always read the same current. -- In a parallel circuit, the ammeter may read a different current when it's moved to a different parallel branch.
in ac circuits power,P=VICOS@ @ is the angle between voltage and current. in dc P=VI V is the voltage I is the current. Power (in Watts) is current (A) x voltage (V)
In a series circuit, the current does not change. It is simple the total voltage divided by the total impedence. However, in a parallel circuit the current splits. More current will go down the path with less impedence, and vice versa. For example, you have two parallel branches, 1 and 2, with resistances R1 and R2 respectively. Also, the total current flowing is I, while the current down each branch is I1 and I2. I1= I(R2)/(R1+R2) I2= I(R1)/(R1+R2) Also note that I1 + I2 = I.
Adding more loads in a parallel circuit increases the current because of Kirchoff's voltage and current laws, and because of Ohm's law...1. Kirchoff's voltage law states that the signed sum of the voltage drops around a series circuit is zero. A consequence of this is that the voltages across elements of a parallel circuit must be the same.2. Ohm's law states that current is voltage divided by resistance. Since the voltage across each new parallel element is the same, the current in that element is known. A consequence of this is that each additional element does not change the current in the other elements.3. Kirchoff's current law states that the signed sum of the currents entering a node is zero. A consequence of this, and 1 and 2 above, is that the currents added by each parallel element increases the total current entering the set of parallel elements.
It depends on weather it is in a parallel or series circuit. In parallel the entire circuit it is in parallel with is shorted out. In series the total resistance decreases by the amount of the resistor that shorted out. Resistors usually open or change value with use.
-- In a series circuit, no matter where you install the ammeter, it will always read the same current. -- In a parallel circuit, the ammeter may read a different current when it's moved to a different parallel branch.
The current in each branch of the circuit will turn and flow in the other direction.
There will be no change, because it is a parallel circuit.
in ac circuits power,P=VICOS@ @ is the angle between voltage and current. in dc P=VI V is the voltage I is the current. Power (in Watts) is current (A) x voltage (V)
In a series circuit, the current does not change. It is simple the total voltage divided by the total impedence. However, in a parallel circuit the current splits. More current will go down the path with less impedence, and vice versa. For example, you have two parallel branches, 1 and 2, with resistances R1 and R2 respectively. Also, the total current flowing is I, while the current down each branch is I1 and I2. I1= I(R2)/(R1+R2) I2= I(R1)/(R1+R2) Also note that I1 + I2 = I.
V=IR where V is voltage, I is current and R is resistance. You want to know what the current will be in a series circuit based on the resistance. You need to know the voltage as well as the resistance, gives you the equation as follows I=V/R So if you have 10 volts and a 1 ohm resistor, the current will be 10 amps. If you increase the resistor to 10 ohms, your current will then be 1 amp. In a parallel circuit, the resistance is equal to the sum of the inverse. For example. If I have two resistors of 2 ohms each in parallel, the equation would be 1/2 + 1/2 = 0.5 + 0.5 = 1 In that particular instance, your current would increase.
Adding more loads in a parallel circuit increases the current because of Kirchoff's voltage and current laws, and because of Ohm's law...1. Kirchoff's voltage law states that the signed sum of the voltage drops around a series circuit is zero. A consequence of this is that the voltages across elements of a parallel circuit must be the same.2. Ohm's law states that current is voltage divided by resistance. Since the voltage across each new parallel element is the same, the current in that element is known. A consequence of this is that each additional element does not change the current in the other elements.3. Kirchoff's current law states that the signed sum of the currents entering a node is zero. A consequence of this, and 1 and 2 above, is that the currents added by each parallel element increases the total current entering the set of parallel elements.
Current decreasesWhen voltage remains constant and resistance increases the current in the circuit will reduce.More informationV=IRwhere V is voltage,I is current andR is resistance.From the above equation,R=V/I, and hence resistance is indirectly proportional to current.Therefore, an increase in resistance would have the effect of decreased current.NB: this holds true only as long as the voltage remains constant.Another opinionHowever, this is only true in the case of a circuit connected in series.When circuits are connected in parallel, the opposite happens. If there is an increase in the amount of resistors in parallel, the total resistance of the circuit then decreases and the current increases subsequently.Yet another viewNo, that's not stated right.If more resistors are added in parallel - so that the circuit's overall total resistance decreases and its total current increases - that is NOT in any way the opposite of what this question is asking about...Let's make this crystal clear, so that there is no confusion: "an increase in the amount of resistors" is NOT the same as "an increase in resistance".So a parallel circuit behaves EXACTLY the same as a series circuit: if its overall resistance increases, the overall current going through the parallel circuit decreases AND if its overall resistance decreases, the overall current going through the parallel circuit increases.Actually, the second opinion is correctIn a parallel circuit, there are more branches to allow electrons back to the power supply, so current increases. With more resistors in a circuit, the overall resistance in a parallel circuit DECREASES.In a series circuit, current is the same throughout. So if more resistors are added, resistance INCREASES and so current DECREASES.
No change in supply voltage as additional resistance is connected in parallel circuit.
It depends on weather it is in a parallel or series circuit. In parallel the entire circuit it is in parallel with is shorted out. In series the total resistance decreases by the amount of the resistor that shorted out. Resistors usually open or change value with use.
In a series circuit, if you open a bulb, current loop will be broken. So, current cannot travel all the wayback, hence no output. But in a parallel circuit, current will be only shared with parallel circuit, but the loop remains closed even if you remove the bulb. So, no change occurs.
Parallel branches each draw a current from the supply. The more branches, the more current is drawn. Adding additional loads to a series circuit increases its resistance, causing its supply current to reduce.