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In a processor these are 120 instructions Bits needed to implement this instructions?
Ramyamaridi
Log2 260 is 8.022, so it would seem that 9 bits are required to handle 260 instructions. In practice, however, the opcode is a multiple of 8 bits, so most instructions are 8 bits, with a few being 16 bits.
Wiki User
∙ 11y ago
Wiki User
∙ 13y agoIt takes 7 bits to implement the opcode space of 120 instructions.
27 = 128
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