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//you tell us and we'll both know

assuming that you have used h-parameter analysis for this ...Vb contains the Ib and the Ie terms which can be expressed ad Ie=(1+Hfe)Ib

then we have

Vb=Hie*Ib + Re*Ie
=Hie*Ib + Re(1+Hfe)Ib
=Ib(Hie+(1+Hfe) Re)

then we can find
Ri as Vb/Ib= Hie+(1+Hfe)*Re

hope that helps....

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Q: In bjt small signal analysis in emitter stablization bias the circuit which have re unbypassed when trying to get zb the impedance why you divided vi by ib although that that both resistances beta r?
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