An array is a group of related elements, with a common variable name. The index is a number that indicates the position of an element within an array: the 1st. element, the 2nd. element, etc. (many languages start counting at zero).
An index is just a notational tool for tracking the members of an array and as such, it can be any number, letter, or symbol you want it to be. To be practical, however, there should be at least two indexes in your array (less it would not be a list, just a lone variable, no?).
For any given type T, the type T[n] declares an array of n type Ts. The array subscript operator allows us to access the individual elements in an array using a zero based index in the range 0 to n-1.
(array.length - 1) will find the index of the last element in an array (or -1 if the array is empty).
Basically, &array[i]; That is, the memory location for an array object with index i. Or, you can do: (array + i);
An array is a container object that holds a fixed number of values of a single type. ... Each item in an array is called an element, and each element is accessed by its numerical index. As shown in the preceding illustration, numbering begins with 0. The 9th element, for example, would therefore be accessed at index 8.
type array-identifier = array[index-type] of element-type; array-identifier : the name of your array index-type : any scaler except real element-type : the type of element The index type defines the range of indices and thus the number of elements to allocate. For example, [0..41] will allocate 42 elements indexed from 0 to 41, thus creating a zero-based array. If you require a one-based array, use [1..42] instead. Regardless of the range of indices, the first element is always at the lowest address of the array (the compiler will convert your index range into a zero-based range automatically). The element-type determines the length of each element in the array. Multiplying the element length by the number of elements gives the total amount of memory allocated to the array.
Since an array cannot contain a negative number of items, the size of an array must be at least 0. So if you ever tried to retrieve the element at a negative index in an array, it would automatically be understood to be out-of-bounds.
(array.length - 1) will find the index of the last element in an array (or -1 if the array is empty).
by using index position we can find the particular element in array.
When you are accessing an array's element.
Basically, &array[i]; That is, the memory location for an array object with index i. Or, you can do: (array + i);
In a complete binary tree (CBT) stored using an array, the parent of an element at index i can be found at index (i-1)/2, assuming the array is 0-indexed. So for an element stored at index 11, the parent node would be stored at index (11-1)/2 = 5.
An array is a container object that holds a fixed number of values of a single type. ... Each item in an array is called an element, and each element is accessed by its numerical index. As shown in the preceding illustration, numbering begins with 0. The 9th element, for example, would therefore be accessed at index 8.
type array-identifier = array[index-type] of element-type; array-identifier : the name of your array index-type : any scaler except real element-type : the type of element The index type defines the range of indices and thus the number of elements to allocate. For example, [0..41] will allocate 42 elements indexed from 0 to 41, thus creating a zero-based array. If you require a one-based array, use [1..42] instead. Regardless of the range of indices, the first element is always at the lowest address of the array (the compiler will convert your index range into a zero-based range automatically). The element-type determines the length of each element in the array. Multiplying the element length by the number of elements gives the total amount of memory allocated to the array.
For an array of length s, the last element has index s-1.
#include<stdio.h> #include<conio.h> main() { int a[100]; int n,largest,index,position; printf("enter the number of elements in the array"); scanf("%d",&n); printf("enter %d elements",n); for(index=0;index<n;index++) scanf("%d",&a[index]); largest=a[0]; position=0; for(index=1;index<n;index++) if(a[index]>largest) { largest=a[index]; position=index; } printf("largest element in the array is %d\n",largest); printf("largets element's position in the array is %d\n",position+1); getch(); }
C++ array indices are zero-based because the first element in any array is offset 0 elements from the start address. The second element is offset by 1 element and the third by 2 elements, and so on. To put it another way, the index refers to the number of elements that come before the desired element. The first element has zero elements before it, so it is index 0. For an array of n elements, the last element is at index n-1.
You can access the array-element via index (or subscript), but it is not possible the other way around.
Since an array cannot contain a negative number of items, the size of an array must be at least 0. So if you ever tried to retrieve the element at a negative index in an array, it would automatically be understood to be out-of-bounds.