I assume you mean CH2=C=CH2 or 1,2-propadiene. The molecule has two equally electronegative substituents attached to the central carbon, so no it is not polar. If it was CH2=C=O, then yes it would be polar, because the oxygen atom pulling the electron cloud toward itself, thus making it slightly negative which make he molecule polar.
H2C=C=CH2, 6 sigma and 2 pi bonds.
No. It is a polar molecule.
It might be tempting to think Benzil is a polar molecule because of the C=O bonds, but the high level of symmetry in the molecule cancels out any overall dipole and leaves the molecule non-polar.
CF3Cl is a polar molecule. There are three C-F polar bond and and C-Cl polar bond. The bond dipoles do not cancel out and hence the compound is a polar molcule.
1. hexane: CH3-CH2-CH2-CH2-CH2-CH32. 3-methylpentane: CH3-CH2-CH(CH3)-CH2-CH33. 2-methylpentane: CH3-CH(CH3)-CH2-CH2-CH34. 2,2-dimethylbutane: CH3-C(CH3(CH3))-CH2-CH3
H2C=C=CH2, 6 sigma and 2 pi bonds.
it is polar
The compound CH2=CH-CH=CH2 when reacts with HBr gives 1,4 addition product, CH3-CH=CH-CH2Br
No. It is a polar molecule.
Well, it's organic. Past that it's difficult to say with certainty. It could be a cyclic diether or diol, it could be an ester, it could be an alkene diether or diol ... the molecular formula alone doesn't provide enough information to be sure.
It might be tempting to think Benzil is a polar molecule because of the C=O bonds, but the high level of symmetry in the molecule cancels out any overall dipole and leaves the molecule non-polar.
Ch2chch3 c=c-c
D. both b and c
this is nothing actually is... CH3-CH2-CH2-O-CH2-CH3 ethyl methyl ether....
Ch3 -ch2 -o-c(o)-ch2-ch2-ch2-ch2-ch2-ch2-ch3
CF3Cl is a polar molecule. There are three C-F polar bond and and C-Cl polar bond. The bond dipoles do not cancel out and hence the compound is a polar molcule.
1. hexane: CH3-CH2-CH2-CH2-CH2-CH32. 3-methylpentane: CH3-CH2-CH(CH3)-CH2-CH33. 2-methylpentane: CH3-CH(CH3)-CH2-CH2-CH34. 2,2-dimethylbutane: CH3-C(CH3(CH3))-CH2-CH3