Potassium chloride can be a solute if is dissolved in water.
Yes, KCl is a solute. It is a compound that dissolves in a solvent, such as water, forming a homogeneous mixture called a solution.
Potassium chloride, KCl, is a salt; it dissolves in water and would be considered a solute when it does so.
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
In a homogeneous mixture, KCl is dissolved uniformly in the solvent, creating a single-phase solution where the KCl particles are evenly distributed and not visible to the naked eye. In a heterogeneous mixture, KCl exists as visible particles suspended in the solvent without fully dissolving, creating a two-phase system where the KCl particles can settle out over time due to gravity.
a. KCl in water b. CH3OH in H2O c. CH2Cl2 in benzene
In a 3.4 M solution, there are 3.4 moles per liter. If you want to make 3 liters of solution, you'll need 3 liter * 3.4 moles/liter = 10.2 moles The molar mass of KCl is 39.098 g/mole K + 35.453 g/mole Cl = 74.551 g/mole KCl To get the number of grams, multiply the number of moles by the molar mass: 10.2 moles * 74.551 g/mole KCl = 760.4202 g = 0.760 kg
Potassium chloride, KCl, is a salt; it dissolves in water and would be considered a solute when it does so.
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
Molarity is moles of solute per L of solution.moles KCl = ( 1.68 M ) ( 0.121 L ) = ( 1.68 mol/L ) ( 0.121 L )moles KCl = 0.203 moles KCl
Molarity = moles of solute/Liters of solution ( 50.0 ml = 0.05 Liters ) 0.552 M KCl = moles/.0.05 liters = 0.0276 moles of KCl
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!
Need mole KCl first. 4.88 grams KCl (1 mole KCl/74.55 grams) = 0.06546 moles KCl =======================now, Molarity = moles of solute/Liters of solution ( 423 ml = 0.423 Liters ) Molarity = 0.06546 moles KCl/0.423 Liters = 0.155 M KCl ------------------
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
The molarity of the solution is calculated by dividing the moles of solute (KCl) by the volume of solution in liters. In this case, molarity = 0.202 mol / 7.98 L ≈ 0.0253 mol/L.
In a homogeneous mixture, KCl is dissolved uniformly in the solvent, creating a single-phase solution where the KCl particles are evenly distributed and not visible to the naked eye. In a heterogeneous mixture, KCl exists as visible particles suspended in the solvent without fully dissolving, creating a two-phase system where the KCl particles can settle out over time due to gravity.
a. KCl in water b. CH3OH in H2O c. CH2Cl2 in benzene
In a 3.4 M solution, there are 3.4 moles per liter. If you want to make 3 liters of solution, you'll need 3 liter * 3.4 moles/liter = 10.2 moles The molar mass of KCl is 39.098 g/mole K + 35.453 g/mole Cl = 74.551 g/mole KCl To get the number of grams, multiply the number of moles by the molar mass: 10.2 moles * 74.551 g/mole KCl = 760.4202 g = 0.760 kg
Mass percent is the ratio of the mass of solute to the total mass of solution expressed as a percent Here we have 4.0 g solute and total mass of solution of 4.0 g + 50.0 g = 54.0 g. So, the mass percent of KCl = 4.0 g/54.0g (x100) = 7.41% (3 sig figs)