The melting point of NaBr is 747 oC.
2 Na + Br2 --> 2 NaBr
yes it is because kbr is just one word not 2.
The answer is 0,0207 mol.
KBr is transparent to IR radiation, most alkali halides are transparent in ir
KOH, NaOH, KCl, KBr, NaBr
NaCl, NaOH, NaBr, KBr, KOH
This does not make a buffer because HBr is a STRONG acid, and for a buffer you need a WEAK acid and the salt of the acid.
Salts of bromine are called bromides and many are known: CaBr2, KBr, NaBr, LiBr etc.
When you flame test the two solutions, any Na solution burns yellow, while any K solution burns violet/purple. So both the KCl and the KBr will burn purple, while both NaBr and NaCl will burn yellow.
No, NaBr is a neutral salt.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
Take your pick of ionic compounds? NaCl, NaFl, NaI, NaBr, LiCl, LiFl, LiI, LiBr KI KCl KBr KFl, keep going down group I and II and halogens, and you will have 24 right off the bat. Take your pick of ionic compounds? NaCl, NaFl, NaI, NaBr, LiCl, LiFl, LiI, LiBr KI KCl KBr KFl, keep going down group I and II and halogens, and you will have 24 right off the bat.
NaBr is a salt.
Sodium bromide (NaBr) is a salt.
The melting point of NaBr is 747 oC.
Sodium and bromine are the elements in sodium bromide (NaBr) compound.