This solution contain 26,3 g NaOH.
The answer is 0,625 moles.
Methyl orange shows yellow color in an NaOH solution.
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
This solution contain 26,3 g NaOH.
It is possible only if you evaporate the water.
The answer is 0,625 moles.
The concentration of this solution (in NaOH) is 40 g/L.
standardization of NaoH
40 grams, this is the 1M NaOH standard laboratory solution.
Methyl orange shows yellow color in an NaOH solution.
100 g of solution containing 50 g of NaOH.
One liter of a one molar solution of NaOH in water contains 40g of NaOH. The quantity must be known.
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
Molarity = moles of solute/volume of solution 0.53 M NaOH = moles NaOH/3.8 Liters = 2.014 moles, or about 80 grams
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH