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Best Answer

Yes.

AND operation

= f(A,B) = AB = A'f(0,B) + Af(1,B)

= A'(0B) + A(1B) = A'0 + AB

OR operation

- f(A,B) = A+B = A'f(0,B) + Af(1,B)

= A'(0+B) + A(1+B) = A'B + A1

NOT operation

- f(A) = A' = A'f(0) + Af(1)

= A'(1) + A(0)

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Q: Is a 2-to-1 mux functionally complete?
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