It's heterozygous.
Heterozygous is when there is a big letter and a little letter, like Bb. Homozygous is when both letters are the same size, like BB or bb.
Heterozygous
A heterozygote means different-joineda homozygote means same-joinedso lets look at this cross. (parent genotype are Bold and italics)---B----bB | BB | Bb |--------------------B | BB | Bb |We see that 2 "joined" zygotes are BB and 2 are BbSO by definition 2 combinations produce a heterozygote "Bb"and 2 produce a homozygote "BB"
The Punnett square for crossing two heterozygous dogs (Bb x Bb) would result in a 25% chance of offspring with homozygous dominant black fur (BB), a 50% chance of offspring with heterozygous black fur (Bb), and a 25% chance of offspring with homozygous recessive brown fur (bb).
To solve a Punnett square for two parents with genotype Bb (heterozygous for the same gene), you would set up a 2x2 grid. The possible combinations in the offspring would be BB, Bb, Bb, and bb. This results in a 25% chance of the offspring being BB (homozygous dominant), a 50% chance of being Bb (heterozygous), and a 25% chance of being bb (homozygous recessive).
The most accurate description of an organism with genotype AaBb is heterozygous. A homozygous genotype is aaBB and AA.
Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
To determine the probability of different offspring from the cross of genotypes BB, Bb, and bb, we first need to clarify the specific cross being made. If we are crossing BB (homozygous dominant) with Bb (heterozygous), the potential offspring would be 50% BB and 50% Bb. If we then cross this with bb (homozygous recessive), the resulting offspring would be 50% Bb and 50% bb. Thus, the probabilities for the offspring would be 50% Bb and 50% bb.
Both parents were heterozygous (Bb). The offspring would statistically be: BB, Bb, Bb, and bb. All but the bb offspring would be black and the bb would be brown.
In genetics, BB represents a homozygous dominant genotype, where both alleles are dominant. Bb represents a heterozygous genotype, where one allele is dominant and one is recessive. bb represents a homozygous recessive genotype, where both alleles are recessive.
The offspring will get the traits of Homozygous BB .
If both parents are heterozygous for brown eyes (Bb), the possible allele combinations for their children can be represented in a Punnett square: BB, Bb, Bb, and bb. This means there is a 1 in 4 chance, or a 25% probability, that their child will inherit the blue eye genotype (bb) and therefore have blue eyes.
Black coat homozygous: BB Black Coat heterozgous: Bb