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Sodium hydrogen phosphate is an acid.

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Q: Is nah2po4 an acid salt or basic salt or normal salt?
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Is Na2HPO4 acidic or basic salt or normal salt?

i don't , it seem be an acid NaH2PO4, Sodium dihydrogen phosphate, is an acid. The two hydrogen atoms can dissociate and lower the ph of a solution. That is to make it more acidic. Once all the hydrogen atoms that can dissociate have been replaced by sodium Na. the formula will look like this Na3PO4, at that point it would be called a 'salt' with a neutral ph.


Why does acetic acid does not form an acid salt but forms a normal salt?

Actually, it will probably tend to form basic salts. Ethanoic acid is a weak acid, so when it reacts with a strong base, it will form a basic salt.


Why is that acetic acid does not form an acid salt but forms a normal salt?

Actually, it will probably tend to form basic salts. Ethanoic acid is a weak acid, so when it reacts with a strong base, it will form a basic salt.


Is Na3PO4 an acidic salt or normal salt?

H3PO4Is phosphoric acid, a strong acid. This would have to react with a strong base, such as NaOH, to produce a salt.3NaOH + H3PO4 --> Na3PO4 + 3H2OThe salt produced is sodium phosphate.


product of neutralisation?

Acid + Basic ----> Salt + Water + Heat


What is RaCO3 Is it an acid base salt acid anhydride or basic anhydride?

RaCO3 is a salt


Is Calcium sulphate an acid salt?

No.it's a normal salt


Is kcl a acid or normal salt?

Potassium chloride is a neutral salt.


Is table salt a basic salt?

No, sodium chloride has no acid-base properties.


NaC2H3O2 base or acid?

It is a salt that is weakly basic.


Is NH4Br basic or acidic?

it is a salt of weak base, ammonium hydroxide and strong acid ,hydrobromic acid. Therefore this salt is acidic in nature.


What does mixing in acid with a base give you?

When mixing an acid and a base you will get a salt and water solution (But this is not the normal water that you would drink or, the normal salt you would put on your chips) . Here is the word equation; acid+ base= salt+ water.