6.02214076×1023
0.220 mole O2
Balanced equation. 2H2 + O2 -> 2H2O 355 grams O2/32 grams = 11.1 moles O2 check for limiting reactant 11.1 moles O2 (2 mole H2/1 mole O2) = 22.2 mole H2 and H2 has no where near that many moles, so limits and drives reaction so, as they are one to one...... 22.2 moles of H2O are produced
Balanced equation first. 4P + 5O2 -> 2P2O5 8.00 mole O2 (2 mole P2O5/5 mole O2) = 3.20 moles P2O5 produced
48.0 g O2 x 1 mole O2/32 g x 6.02x10^23 molecules O2/mole O2 = 9.03x10^23 molecules of O2
The mass of 3.2 moles O2? The atoms in 3.2 moles O2 Could be other things, I guess, but I will do these two. 3.2 moles O2 (32 grams/1 mole O2) = 102.4 grams of gaseous oxygen -------------------------------------------- 3.2 mole O2 (6.022 X 1023/1 mole O2) = 1.9 X 1024 atoms of gaseous oxygen --------------------------------------------------
4NH3 + 5O2 -> 4NO + 6H2O I suspect NH3 limits. Let's see. 5.15 O2 ( 4 mole NH3/5 mole O2) = 4.12 mole NH3 you do not have that much ammonia, so it limits and drives the reaction. 3.80 mole NH3 (4 mole NO/4 mole NH3) = 3.80 moles of NO made
A mole of oxygen atoms has a mass of approximately 16 grams. A mole of O2 has a mass of approximately 32 grams. A mole is 6.02 x 1023 particles and as such a mole of oxygen atoms has only half the mass of a mole of oxygen molecules.
Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------
C + O2 ------> CO2 is the reaction equation. 1 mole of C + 1 mole of O2 makes 1 mole of CO2.
82.5 grams O2 (1 mole O2/32 grams)(6.022 X 10^23/1 mole O2) = 1.55 X 10^24 atoms of O2
150.0 g O2 x 1 mole O2/32 g O2 = 4.688 moles O2