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The mass of 3.2 moles O2? The atoms in 3.2 moles O2 Could be other things, I guess, but I will do these two.
3.2 moles O2 (32 grams/1 mole O2)
= 102.4 grams of gaseous oxygen
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3.2 mole O2 (6.022 X 1023/1 mole O2)
= 1.9 X 1024 atoms of gaseous oxygen
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∙ 12y ago
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How many moles are in 64 g of oxygen?
4.80 grams O2 (1 mole O2/32 grams ) = 0.150 moles of O2
How many moles of H2O are product from reaction of 355 g of O2?
Balanced equation. 2H2 + O2 -> 2H2O 355 grams O2/32 grams = 11.1 moles O2 check for limiting reactant 11.1 moles O2 (2 mole H2/1 mole O2) = 22.2 mole H2 and H2 has no where near that many moles, so limits and drives reaction so, as they are one to one...... 22.2 moles of H2O are produced
How do you convert an element to moles?
to convert an element to moles you need to setup and equation, for our example we will be using 5g of O2 or oxygen. You need to know what O2's molar mass is as well, it is 32g. So the equation would be 5g of O2 / 32 = .16 moles of O2. So to convert moles to grams all you do is multiply the moles given by the molar mass of the element/compound and you have your grams Hoped this helped : )
What is the mass of water when 4gm hydrogen and 64gm oxygen combined together nd how?
Balanced equation first.2H2 + O2 --> 2H2OGet moles products.4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H264 grams O2 (1 mole O2/32 grams) = 2.000 moles O2I suspect hydrogen gas of limiting and driving the reaction.1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)= 36 grams water produced====================
How many grams of 02(g) are needed to completely burn 23.7 g of C38H(g)?
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
What is the number of moles in 32 grams of O2?
There are 1.0001 moles.
How many moles in 150.0 g O2?
150.0 g O2 x 1 mole O2/32 g O2 = 4.688 moles O2
How many grams of O2 are in 15 moles of O2. with work shown?
15 moles O2 (32 grams/1 mole O2) = 480 grams
How many moles are in 64 g of oxygen?
4.80 grams O2 (1 mole O2/32 grams ) = 0.150 moles of O2
What mass of oxygen two moles of O2 molecules have molor mass of O2 is 32 grms per mole?
64g
How many moles of H2O are product from reaction of 355 g of O2?
Balanced equation. 2H2 + O2 -> 2H2O 355 grams O2/32 grams = 11.1 moles O2 check for limiting reactant 11.1 moles O2 (2 mole H2/1 mole O2) = 22.2 mole H2 and H2 has no where near that many moles, so limits and drives reaction so, as they are one to one...... 22.2 moles of H2O are produced
4NH3 7O2 4NO2 6H2O how many grams of oxygen are necessary to produce 4.50 moles of NO2?
4.50 moles NO2 X (46 grams NO2) / (1 mole NO2) x (4 moles NO2) / (7 moles O2) x (1 mole O2) / (32 gm O2) = 3.70 grams O2
How many moles of oxygen are represent in 0.16 g of oxygen gas?
using the equation moles=mass/molar mass (since its in gas form) O2 => 16*2 =32 0.16/32=0.005 moles :)
How do you convert an element to moles?
to convert an element to moles you need to setup and equation, for our example we will be using 5g of O2 or oxygen. You need to know what O2's molar mass is as well, it is 32g. So the equation would be 5g of O2 / 32 = .16 moles of O2. So to convert moles to grams all you do is multiply the moles given by the molar mass of the element/compound and you have your grams Hoped this helped : )
How many moles of acetylene (C2H2) are needed to completely react with 12 moles of oxygen?
The reaction is:2 C2H2 + 5 O2 = 4 CO2 + 2 H2OThe answer is 4,8 moles oxygen.
What is the mass of water when 4gm hydrogen and 64gm oxygen combined together nd how?
Balanced equation first.2H2 + O2 --> 2H2OGet moles products.4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H264 grams O2 (1 mole O2/32 grams) = 2.000 moles O2I suspect hydrogen gas of limiting and driving the reaction.1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)= 36 grams water produced====================
How many grams of 02(g) are needed to completely burn 23.7 g of C38H(g)?
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
