It's beta decay. Actually, it's beta minus decay. A neutron in the nucleus of thorium-234 undergoes beta minus decay and changes into a proton with the subsequent release of an electron, an antineutrino and some energy. The transformation of a neutron in the thorium nucleus into that proton creates another element. You'll recall that the identity of an element is determined solely by the number of protons in its nucleus. And our thorium atom has now become a protractinium-234 atom. Links are provided below for more information.
Uranium-238 decays by alpha emission into thorium-234, which itself decays by beta emission to protactinium-234, which decays by beta emission to uranium-234. Uranium-234 decays by alpha emission to Thorium-230, which then decays by alpha emission to Radium-226, then to Radon-222, again by alpha decay. After several more alpha and beta decays resulting in various isotopes of polonium, astatine, bismuth, thallium, and lead, the series ends with the stable isotope lead-206.
A) Beta Decay - As the mass number is the same and it has a charge of -1 B) Fusion - Because the resulting pruduct has a greater mass number nad atomic number than the 2 reactants C) Alpha Decay - As the mass number has dropped by 4 and there is a helium particle present (the product released through the process of alpha decay)
U238 is actually extremely stable with a half life of 4.468 billion years. But of the little that does decay, it decays like this...
U238 -> Th234 + He4 + 4.267 MeV
This is done through alpha decay.
No, 234Th decays to 234Pa via beta decay. If it DID decay via alpha emission, it wouldn't decay to 234Pa, because it would lose 4 Atomic Mass units, bringing it down to 230Ra, which as far as I know doesn't exist.
It is an example of beta decay, specifically beta-minus decay, in which a nucleus emits an electron and a neutron turns into a proton. The addition of another proton changes the atom of one element into an atom of a different element. When an atom of thorium-234 undergoes beta-minus decay, it emits an electron and it gains a proton, producing a protactinium-234 atom as a result. Its atomic number is 59, whereas the atomic number of thorium is 58.
92Au 282Xe +13S
By alpha decay polonium-214 is transformed in lead-210. Po-214--------------alpha--------------Pb-210
Radon-198 does not decay via beta decay. It is thought to decay by alpha decay, but that is not certain. The equation would be ... 86198Rn -> (Alpha, T1/2 = 86 ms) -> 84194Po + 24He2+
Th-230(alpha)Ra-226.
The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
Plutonium-241 decays by both beta- and alpha decay. For beta- decay the equation is ...94241Pu -> 95241Am + e- + v-eNot asked but answered for completeness sake, for alpha decay the equation is ...94241Pu -> 92237U +24He2+
The equation for the alpha decay of 233Pu:94233Pu --> 92229U + 24He2+where the alpha particle is represented as a helium nucleus.Note that 233Pu decays by alpha decay with a probability of only 0.12%. The other 99.88% is Beta+ decay.
Lead-210 decays by alpha or beta decay. The equation for the alpha decay of 210Pb is: 82210Pb --> 80206Hg + 24He representing the alpha particle as a helium nucleus. The equation for the beta decay of 210Pb is: 82210Pb --> 83210Bi + -10e where the -10e is an electron.
There is no equation. Calcium-42 is stable and does not decay. Calcium is also much to light for alpha decay, which requires elements heavier than nickel, so no isotope of calcium undergoes alpha decay.
Uranium-239 does NOT decay by alpha decay, it decays only by beta and gammadecay.
92Au 282Xe +13S
The equation for the alpha decay of 213At: 85213At --> 83209Bi + 24He where the alpha particle is represented as a helium nucleus.
The equation for the alpha decay of 265Bh is:107265Bh --> 105261Db + 24He where the 24He is an alpha particle or helium nucleus.
The equation for the alpha decay of 222Rn is: 86222Rn --> 84218Po + 24He Where He represents the alpha particle, which can also be viewed as a Helium nucleus.
Mercury-201 is stable and does not decay.
parent element