yes they are balanced
2Pb + O2 ----->2PbO then 2PbO + O2 ------> 2PbO2 some mixed oxide will be formed also 2PbO + PbO2 ----->Pb3O4
Yes . That is true ;) 2Pb0+C->2Pb+CO2 Good luck ;)
When lead oxide is heated with carbon, carbon dioxide and lead are formed as the products 2PbO+C -->CO2+2Pb
2PbS+3O2 goes to 2SO2+ 2PbO
PbO2 + 4HBr ---- 2H2O + Br2 + PbBr2
2Pb + O2 ----->2PbO then 2PbO + O2 ------> 2PbO2 some mixed oxide will be formed also 2PbO + PbO2 ----->Pb3O4
2PbO ---> 2Pb + O2
PbO ---> Pb + O2 Balanced 2Pbo ---> 2Pb + O2
Pb(NO3)2(aq) + 2NaOH(aq) -->Pb(OH)2(s) + 2NaNO3(aq)
2SO2 + 2PbO ==
2Pb(NO3)2---> 2PbO + 4NO2 + O2 2Pb(NO3)2 when heated produces 2PbO+NO2+O2 for the part that says "when heated produces" substitute it with an arrow and then you"ll have the equation
2PbO + C ------> 2Pb + CO2 so metallic lead and carbon dioxide.
the equation for the decomposition of lead ii nitrate by heating is: 2Pb(NO3)2 - - - ->2PbO + 4NO2 + O2
Lead Nitrate when heated will decompose forming lead oxide, nitrogen oxide and oxygen. Equation: 2Pb(NO3)2 will give 2PbO + 4NO2 + O2
Yes . That is true ;) 2Pb0+C->2Pb+CO2 Good luck ;)
When lead oxide is heated with carbon, carbon dioxide and lead are formed as the products 2PbO+C -->CO2+2Pb