No, XOR gate is a not a universal gate. There are basically two universal gates NAND and NOR.
xor and xnor gates are derived from not gate
yes... xor is derived gate from primary gates
If you're allowed to prove this the easy way (by showing you can use XOR and AND to create the set of AND, OR, and NOT), this is pretty straightforward. x AND y = x AND y (of course) x OR y = (x XOR y) XOR (x AND y) NOT x = x XOR 1 Also, (x AND y) XOR 1 is equivalent to x NAND y, which is a universal gate.
All other logic gates can be made using XOR and XNOR, but to get NOT, you need to do (input) XOR 1 or (input) XNOR 0, but with NAND, you don't need 1: (input) NAND (input).
its not
XOR (Exclusive OR) gate is exclusively for either. OR allows 10, 01, 11. XOR allows 10 or 01, but not 11.
XOR (Exclusive OR) gate is exclusively for either. OR allows 10, 01, 11. XOR allows 10 or 01, but not 11.
1 gate.
XORing X with 1 gives X', i.e., NOT(X). If we are able to construct a NAND (AND) using XOR, we can also obtain AND (NAND) from it, which makes XOR a universal gate since inverted inputs to a NAND (AND) will give OR (NOR). However XOR is not a universal gate! Therefore we cannot obtain NAND (AND) using XOR. :-) By, Tirtha Sarathi Ghosh Class 10 IIT Kanpur Aspirant
yes
For 2-input EX-OR gate, if one input is A, the other input is B, and the output is Y. Then the Boolean expression for EX-OR (XOR) function (gate) is Y=A⊕B The output Y is true if either input A or if input B is true, but not both.Y= ( (A and NOT B) or (NOT A and B) ) ;
XOR