The formula for the Fibonacci series is
Fn = Fn-1 + Fn-2 for n ≥ 2 with F0 = 0 and F1 = 1.
In layman's terms, in the Fibonacci series each successive number is the sum of the previous two numbers, starting with 1. So we have 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 etc
To do this in Java or any computer program you will need to create a recursive program, one that picks up previous values. This is quite easy, even for a beginner, once one grasps the Fibonacci fundamentals. Here is an example in Java:
public class Fibonacci {
public static long fib(int n) {
if (n <= 1) return n;
else return fib(n-1) + fib(n-2);
}
public static void main(String[] args) {
int N = Integer.parseInt(args[0]);
for (int i = 1; i <= N; i++)
System.out.println(i + ": " + fib(i));
}
}
For n, enter the number of values required, otherwise the increasing values of the results will overflow the parameters of the data display!
This code can be adapted for any progamming language, e.g. pascal, basic etc. One can even use the principles to construct a spreadsheet that will show the Fibonacci series in successive rows in Excel, for example.
// Print out the first N Fibonacci numbers in the order:
// 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765
public static final void printFib(final int N) {
int f0 = 0;
int f1 = 1;
for (int i = 0; i < N; ++i) {
System.out.println(f0);
final int temp = f1;
f1 += f0;
f0 = temp;
}
}
Well, you might use recursion, but that would be exceedingly inefficient. A loop would be much better in this case. The only advantage I see is for didactical purposes, that you practice recursion. Something like this; I didn't try it:
// Call the class MyMath.fib()
int fib(int number)
{
if (number <= 2) return 1;
else return fib(number - 1) + fib(number - 2);
}
Note: A recursive function (or method) is one that invokes itself.
Well, you might use recursion, but that would be exceedingly inefficient. A loop would be much better in this case. The only advantage I see is for didactical purposes, that you practice recursion. Something like this; I didn't try it:
// Call the class MyMath.fib()
int fib(int number)
{
if (number <= 2) return 1;
else return fib(number - 1) + fib(number - 2);
}
Note: A recursive function (or method) is one that invokes itself.
Well, you might use recursion, but that would be exceedingly inefficient. A loop would be much better in this case. The only advantage I see is for didactical purposes, that you practice recursion. Something like this; I didn't try it:
// Call the class MyMath.fib()
int fib(int number)
{
if (number <= 2) return 1;
else return fib(number - 1) + fib(number - 2);
}
Note: A recursive function (or method) is one that invokes itself.
Well, you might use recursion, but that would be exceedingly inefficient. A loop would be much better in this case. The only advantage I see is for didactical purposes, that you practice recursion. Something like this; I didn't try it:
// Call the class MyMath.fib()
int fib(int number)
{
if (number <= 2) return 1;
else return fib(number - 1) + fib(number - 2);
}
Note: A recursive function (or method) is one that invokes itself.
Here is a function to generate the nth Fibonacci number, using a recursion:
public long F (int n)
{
if (n 1)
{
return n;
}
else
{
return F (n - 1) + F (n - 2);
}
}
Note that if n < 0, the function doesn't work. You could also program it by the algebraic formula for the nth Fibonacci number, as follows:
public long F (int n)
{
double a = Math.sqrt (5); //to save code
return (long) (Math.pow ((1 + a) / 2, n) - Math.pow ((1 - a) / 2, n)) / a;
}
The Fibonacci series is not a good candidate for solution using a multithreaded program. This is because each term is dependent on the prior two terms, making it impossible to keep more than one thread unblocked at any one moment of time.
Set two variables "a" and "b" to the starting number of the Fibonacci series, for example, 1 and 1. Then, repeatedly (i.e., in a loop) set:
sum = a + b;
b = a;
a = sum;
... and print the sum (or equivalently, variable "a").
Well, you might use recursion, but that would be exceedingly inefficient. A loop would be much better in this case. The only advantage I see is for didactical purposes, that you practice recursion. Something like this; I didn't try it:
// Call the class MyMath.fib()
int fib(int number)
{
if (number <= 2) return 1;
else return fib(number - 1) + fib(number - 2);
}
Note: A recursive function (or method) is one that invokes itself.
Here is a recursive way of writing Fibonacci series
f(n) = f(n-1) + f(n-2)
A Program in Java that spawns multiple threads is called a multithreaded program in Java.
Obviously Heap Memory
class Program { static void Main(string[] args) { int n1, n2, n3,i; n1 = 0; n2 = 1; for (i = 1; i <= 20; i++) { n3 = n1 + n2; if (n3 <= 200) { Console.WriteLine(n3); n1 = n2; n2 = n3; } } Console.ReadKey(); } }
You mean you have written a program, but you don't understand it? Well, how could I explain it without seeing it?
Lex is a parser generator tool. Its basically a program that generates the lexers.
A multithreaded program is one that has multiple threads in execution. They may execute parallel to one another or totally without relation to one another. In Java you can create multithreaded programs using Java threads.
A Program in Java that spawns multiple threads is called a multithreaded program in Java.
Obviously Heap Memory
/*WAP to display Fibonacci series*/ #include<stdio.h> #include<conio.h> void main() { int i,a=0,b=1,c; scanf("%d",&n); printf("%d\n%d",a,b); for(i=0;i<n;i++) { c=a+b; a=b; b=c; printf("\n%d",c); } getch(); }
class Program { static void Main(string[] args) { int n1, n2, n3,i; n1 = 0; n2 = 1; for (i = 1; i <= 20; i++) { n3 = n1 + n2; if (n3 <= 200) { Console.WriteLine(n3); n1 = n2; n2 = n3; } } Console.ReadKey(); } }
Exactly what do you mean by 'C program in Java'
//to generate Fibonacci series upto a range of 200....(in C).... #include<stdio.h> main() { int a,b,c,i; a=0; b=1; printf("\n FIBONACCI SERIES .....\t"); i=1; while(i<=(200-2)) { c=a+b; printf("\t%d",c); a=b; b=c; i++; } }
You mean you have written a program, but you don't understand it? Well, how could I explain it without seeing it?
see the program
i dn't know. haha
Java is called multithreaded because it allows the programmer to define multiple threads of execution manually. The main program would continue to execute as one thread and we can speed up the processing by declaring individual threads. Threads in Java can be created in two ways: 1. By extending the Thread class & 2. By implementing the Runnable interface
Lex is a parser generator tool. Its basically a program that generates the lexers.