The oxidation state of boron is either three electrons or one electron. Boron has an valence electron configuration of ns2np1.
+3 oxidation state
+3 oxidation state
The +3 oxidation state is stable-
Boron (B, atom number 5, the 1ST member of group 13) has an oxidation state of +3, it is rather a metaloid, even more than Al (2nd member), so it forms an acidic oxide B2O3.
+3
B2 (O2)2 (OH)4 +12 -8 -4 going off this i'd say boron's O.S is +6
The oxidation state of boron is either three electrons or one electron. Boron has an valence electron configuration of ns2np1.
+3 oxidation state
+3 oxidation state
The +3 oxidation state is stable-
Boron (B, atom number 5, the 1ST member of group 13) has an oxidation state of +3, it is rather a metaloid, even more than Al (2nd member), so it forms an acidic oxide B2O3.
Boron has an oxidation number of +3. It will try to lose the three valence electrons that it has, so that it is stable. Electrons are negative, and removing them would make the oxidation number positive.
+3
Generally third A group elements in the periodic table exhibit +3 oxidation state but Boron exhibit negative oxidation state also . The stable oxidation state of Tl is +1. It exhibit +3 also but +1 is more stable than +3. RGUKT IIIT NUZVID N091528
No, although boron can be oxidized the term rusting is reserved for the oxidation of iron and iron alloys.
The compound has no charge. This means that the positive oxidation numbers must equal the negative oxidation numbers. 'H' always has an oxidation number of +1. There are three of these atoms in the compound giving +3. To cancel out this positive number, the 'B' must equal -3.