void *array[2]; printf ("array[%d]=%p\n", i, array[i]);
Sort the array then traverse the array, printing the element values as you go.
Accept 5 numbers in an array and display it.
The value of the kth smallest element in the array is the kth element when the array is sorted in ascending order.
You cannot delete from an array.
which element of the array does this expression reference num[5]
by using index position we can find the particular element in array.
(array.length - 1) will find the index of the last element in an array (or -1 if the array is empty).
To search, you would start with the first element of the array and compare it with the target value. If the first element matches the target, you found it. If not, you would move to the next element in the array and repeat the process until either you find the target or exhaust all elements in the array.
The root of the tree is stored in array element [0]; for any node of the tree that is stored in array element [i], its left child is stored in array element [2*i], its right child at [2*i+2]
Every element of a pointer array is a pointer, therefore to access the memory being pointed at by an element, dereference the element. For example: #include<iostream> int main (void) { int* a[10] = {nullptr}; for (int i=0; i<10; ++i) { a[i] = new int (i+1); } std::cout << "Address of array:\n"; std::cout << "a = 0x" << &a << std::endl; std::cout << "Address of each element in the array:\n"; for (int i=0; i<10; ++i) { std::cout << "a[" << i << "] = 0x" << &a[i] << std::endl; } std::cout << "Value of each element in the array:\n"; for (int i=0; i<10; ++i) { std::cout << "a[" << i << "] = 0x" << a[i] << std::endl; } std::cout << "Dereferenced value of each element in the array:\n"; for (int i=0; i<10; ++i) { std::cout << "a[" << i << "] = " << *a[i] << std::endl; } for (int i=0; i<10; ++i) { delete a[i]; } }
By returning a pointer to the first element of the array.