void *array[2]; printf ("array[%d]=%p\n", i, array[i]);
Sort the array then traverse the array, printing the element values as you go.
Accept 5 numbers in an array and display it.
You cannot delete from an array.
by using index position we can find the particular element in array.
which element of the array does this expression reference num[5]
(array.length - 1) will find the index of the last element in an array (or -1 if the array is empty).
The root of the tree is stored in array element [0]; for any node of the tree that is stored in array element [i], its left child is stored in array element [2*i], its right child at [2*i+2]
The search for the first array element begins at the assembly plant. As they array is being constructed, the element itself is one of the first components to be completed.
Every element of a pointer array is a pointer, therefore to access the memory being pointed at by an element, dereference the element. For example: #include<iostream> int main (void) { int* a[10] = {nullptr}; for (int i=0; i<10; ++i) { a[i] = new int (i+1); } std::cout << "Address of array:\n"; std::cout << "a = 0x" << &a << std::endl; std::cout << "Address of each element in the array:\n"; for (int i=0; i<10; ++i) { std::cout << "a[" << i << "] = 0x" << &a[i] << std::endl; } std::cout << "Value of each element in the array:\n"; for (int i=0; i<10; ++i) { std::cout << "a[" << i << "] = 0x" << a[i] << std::endl; } std::cout << "Dereferenced value of each element in the array:\n"; for (int i=0; i<10; ++i) { std::cout << "a[" << i << "] = " << *a[i] << std::endl; } for (int i=0; i<10; ++i) { delete a[i]; } }
By no means; you can access any random array element. If you have ever seen examples which process them in order, it is because of the following: when the order doesn't matter (for example, you want to calculate the sum of all the array elements), it is easiest to process them in order.
By returning a pointer to the first element of the array.