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1. A lone pair on oxygen of water attacks a carbon in acetic anhydride, forcing one of the bonds in the carbonyl group (of acetic anhydride) to move onto its oxygen (oxygen of carbonyl group). The oxygen now has a negative charge and water is attached to the carbon that was once doubly bonded to oxygen. The water now has a positive charge, making it an oxonium ion.

2. The lone pair of electrons on the negatively charged oxygen (of the former carbonyl group) moves back down, forming a double bond again with carbon.

3. Carbon now has a negative charge so it has to get rid of it by breaking its bond with oxygen (the one in the middle of the anhydride). You now have 2 molecules.

4. The positive charge of water has to also go away so it loses a hydrogen. You now have one molecule of acetic acid.

5. The hydrogen attaches onto the oxygen that was broken away from carbon (but still attached to the carbonyl group of the other untouched carbon). And you now have your second molecule of acetic acid.

So for every mole of acetic anhydride and water, you form 2 moles of acetic acid.

It may be hard to understand this but i have a link for you if you are still confused.

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Q: Reaction mechanism of acetic anhydride with water?
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