No, not really. Diffusion works when molecules move from an area of higher concentration to an area of lower concentration. They move independently of one another. So even if you have a high level of NaCl, the glucose concentration will diffuse in the same manner.
diffusion coefficient nacl in water at difrent concentration
i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2
Glucose
Glucose (Melting point: 146° C) will melt faster than NaCl (Melting point: 801° C)
5% NaCl solution is unusually high. And because all living organisms seek to maintain an isotonic balance with their environment,osmotic diffusion will occur in order to re-establish this balance.Hence,there will be a diffusion down the gradient i.e. from the medium containing the NaCl solution,into the bacterial cell which has solutes dissolved in it but insufficient to even out this balance.The end result will then be lysis or bursting of the bacterial cell,as it gorges in the NaCl to maintain equilibrium.
No it does not
No it doesn't.
Did NaCl require a transport protein for diffusion?
starch, sucrose, glucose, water, NaCl
no it does not
diffusion coefficient nacl in water at difrent concentration
i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2
Glucose
The
Because NaCl produces double no of particles(Na+ and Cl-) in solution as compare to Glucose (C6H12O6)
yes
suspended in a solution with the following composition: 10% NaCl, 10% glucose and 40% albumin.