Formula: BaI2
Formula: PbI2
2 KBr + BaI2 ----> 2 KI + BaBr2
The anion of barium iodide is iodide (I-).
The balanced chemical equation for the reaction between barium acetate and potassium iodide is: Ba(CH3COO)2 + 2KI -> BaI2 + 2KCH3COO
BaI2 is the chemical formula for Barium Iodide.
In a single replacement reaction between bromine and barium iodide, bromine will replace iodine in barium iodide, forming barium bromide and iodine gas. The balanced chemical equation for this reaction is 2Br₂ + BaI₂ → 2BaBr + I₂.
Yes, barium iodide is soluble in water. It will dissolve and dissociate into barium ions (Ba2+) and iodide ions (I-) in solution.
Unbalanced: KBr + BaI2 --> KI + BaBr2Balanced: 2KBr + BaI2 --> 2KI + BaBr2
Compound Bal2 is also known as Barium iodide.
The compound BaI2 is called barium iodide. It is composed of a barium cation (Ba2+) and two iodide anions (I-).
The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2