specific heat of ice = 2.09 J/g/degree
2.09 J/g/deg x 800 g x 5 deg = 8360 J = 8.4 kJ
∆Hfusion = 334 J/g
0.8kg x 334 J/g x 1000 g/kg x 1 kJ/1000 J = 267 kJ
8.4 kJ + 267 kJ = 275.4 kJ
.02 btu
Approx 2940 Joules.
1 calorie increases 1 gram of water by 1 degree celsius. 4.18 Joules are needed to increase the temperature of 1 gram of water by 1 degree celsius. To reduce the 1 gram of water 1 degree celsius it would have to give off 1 calorie of energy. To calculate the energy multiply the mass in grams of water by 4.18 and by the change in temperature. The energy = 4.18 x m x change in T. The answer is in Joules. If you are using calorie as the unit of energy, replace 4.18 J by 1 C. Note that food is measured in kilocalories (Calories) not metric calories.
that means more energy is needed to raise the temperature of 1kg of liquid from 1 Celsius than water.
Quantity of Energy= mass x temperature change x specific heat capacity For example: Find the amount of energy needed to raise the temperature of 0.20 kg of lead by 15 degree Celsius if the specific heat capacity of lead is 0.90 J/g degree Celsius. Answer: J=200g x 15 degree Celsius x 0.90 J/g degree Celsius = 2700 J
raise the temperature of the body by 1 Celsius
.02 btu
A calorine is the amount of energy needed to raise the temperature of 1gram of water 1 degree celsius.
phase change
42 J
mmmm enthalpy
42 J
Heat of vaporization of water is 40.7 kJ/mol so convert grams of water to moles of water and then convert moles of water to kJ of energy using the above fact. 10g H2O * (1mol/1.008*2+16)=mol H20
A calorie is the amount of energy that needed to raise the temperature of one gram of water one degree Celsius. The Joule is the SI unit for energy.
The amount of heat necessary to raise 1 gram of a substance by 1 degree Celsius is known as?
sunlight.
65 Celsius for 4 weeks