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There is no anode and/or cathode when you simply have a tin can in air. There has to be two poles (usually 2 metals that differ in reduction potential). Here you have only 1 metal. But, in a voltaic (galvanic) cell, oxidation takes place at the anode, and reduction takes place at the cathode.

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Q: The reaction that occur on exposure of a tin can to air and moisture after the tin can has been scratched which reaction occur on the anode and which occur on the cathode?
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Related questions

How does a battery run electronics?

When an electronic device is connected to a battery, an electrochemical reaction occurs between the anode, cathode and electrolyte. The reaction in the anode creates electrons, and the reaction in the cathode absorbs them.


What occurs at the cathode of the galvanic cell?

The reduction half-reaction of a redox reaction


What forms at the cathode during electrolysis of a metal compound?

reduction reaction.


What occurs at the cathode of a galvanic cell?

An oxidation half-reaction


How a battery cause electron in move in a circuit?

It is an oxidation/reduction reaction. Electrons flow from anode to cathode.


What happens at the anode and cathode of a dry cell?

Oxidation occurs at the anode ("an ox") and reduction occurs at the cathode ("red cat").See the Web Link to the left for the specific reaction in a dry cell.


How is the metal used in an anode different from the metal used in a cathode?

Anode is positive and cathode is negative. Cathode is the longest led frame. Anode is where the oxidation reaction takes place while cathode is where the reduction reaction takes place or in a galvanic corrosion the anode is the metal that corrodes while the cathode is protected.


What are the products of the electrolysis of aqueous lead nitrate?

Oxygen on the anode and lead on the cathode. Since it's electrolysis, the reaction is not spontaneous.


Why sulpuric acid is used in battery?

In a battery, there is a cathode, that gives off electrons in a chemical reaction, and an annode, which absorbs electrons in a complimentary chemical reaction. A car battery uses lead (which I will call by its chemical symbol Pb) as the cathode, and lead oxide (PbO) as the annode, both of which are bathed in Sulphuric acid. Lead is oxidized by water in the reaction Pb + H2O = PbO + 2H+ + 2e- (the symbol H+ stands for a hydrogen ion, and e- stands for electrons). The reaction at the annode is PbO + 2H+ + 2e- = Pb + H2O This regenerates the lead, making the car battery rechargable. The Sulphuric acid is a source of H+ which is used to get the reaction going at the annode (the cathode reaction is also a source of H+, but the reaction at the annode requires a large amount of H+ to get going) so Sulphuric acid can be considered a catalyst for this reaction.


When finding the emf of a redox reaction by Ered cathode - Ered anode and a half-reaction is reversed on the chart do you flip the sign of its reduction potential?

No, because the chart shows reduction potentials. Ered cathode - Ered anode = emf just requires you to plug in the reduction potentials the way they are. A common equation is Ered cathode + Eox anode = emf, in which case you would have to flip the sign of the anode's reduction potential, since you would need its oxidation potential. But the equation Ered cathode - Ered anode = emf is simpler and probably formed to be that way.


What is the equation for cathodic reaction?

During electrolysis a cation moves towards cathode where it accepts the electrons and becomes reduced. M+ + e- ------> M


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