The value of a resistor with 5 volts across it and 20 milliamperes of current flowing through it is 250 ohms.
Ohm's Law:
E = I R
R = E/I
Facts missing. Need two of three values. The resistors value. The voltage across it. The current flowing through it. P=I^2*R. P=E^2/R
Who can tell? The power rating of a resistor simply tells us the maximum power that resistor is capable of handling; it doesn't tell us anything about the actual power being produced for any given current. So, to find out the voltage drop across that resistor, you will need to find out its resistance, and multiply this value by the current you specify.
When resistors are connected in series in a circuit . the voltage drop across each resistor will be equal to its resistance, as V=IR, V is direct proportional to R. An A: The relationship is that the current will divide for each paths in a parallel circuit and the voltage drop across each will be the source voltage. In a series circuit the current will remain the same for each component but the voltage will divide to reflect each different component value. And the sum of all of the voltage drops will add to the voltage source
5 A Q / t = I so 1200/4*60 = 5 A
To measure the value of a resistor, apply a voltage and measure the voltage across the resistor and the current through the resistor. Use Ohm's law: Resistance equals Voltage divided by Current. Start with a small voltage and increase gradually until a reading is obtained, but be careful that the power dissipation (watts = volts times amperes) of the resistor is not exceeded. Simpler solution: Use an ohmeter.
Two resistors wired in series (no mater if they have the same resistor value or not) will always have the same amount of current flowing through them. Therefore, the current flowing through the second resistor will be equal to the current flowing through the first one. The current through every component in a series circuit is the same. The voltage across every component in a parallel circuit is the same.
as the given cells have the same current flowing in through them (current flowing through the cells connected in series is equal to the current flowing when connected in parallel ) equate the formula's of cells connected in series and cells connected in parallel.thus by equating we get the value of the internal resistor as 2 ohms.
Write down the Ohm's law expression of "V = I * R" where "V" is the voltage drop across shunt resistor, "I" is the current flowing through shunt and "R" is the shunt resistance.Substitute value of voltage "V" and current "I" in the Ohm's law expression. For example, if voltage across shunt is 10 volts and current flowing through it is 1 ampere, then the expression is 10 = 100 * R.Divide the expression throughout by 100 to calculate the "R" value. Using a calculator, find the value of "R." From the example, the value of "R" will be 0.1 ohm, which is the value of shunt resistor.
Facts missing. Need two of three values. The resistors value. The voltage across it. The current flowing through it. P=I^2*R. P=E^2/R
ohm meter puts current thru a resistor to measure voltage drop E / I = R if the circuit already has current flowing the numbers are meaningless
Who can tell? The power rating of a resistor simply tells us the maximum power that resistor is capable of handling; it doesn't tell us anything about the actual power being produced for any given current. So, to find out the voltage drop across that resistor, you will need to find out its resistance, and multiply this value by the current you specify.
sorry - no can do. The value of a resistor is dependent upon the amount of current flowing through it. To drop the a.c. voltage as you have stated would require a drop-down transformer.
The current can't be calculated from the information given in the question.The power rating of a resistor is the maximum power it can dissipate before it overheatsand its resistance possibly changes permanently. The power rating is not the amount ofpower it always dissipates.So, all we really know about the resistor in the question is that its resistance is 21 ohms.And all we can say about the current through it is:Current through the resistor = (voltage between the ends of the resistor) divided by (21).
A current limiter. Commonly used in well designed power supplies to make the power supply "Fold over" if output current exceeds a safe value. Commonly use a low value resistor in series with the output, and a circuit that senses the voltage across it. Although the above answer describes a circuit to limit current, the device that limits the amount of current flowing through it is a resistor.
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
When resistors are connected in series in a circuit . the voltage drop across each resistor will be equal to its resistance, as V=IR, V is direct proportional to R. An A: The relationship is that the current will divide for each paths in a parallel circuit and the voltage drop across each will be the source voltage. In a series circuit the current will remain the same for each component but the voltage will divide to reflect each different component value. And the sum of all of the voltage drops will add to the voltage source
5 A Q / t = I so 1200/4*60 = 5 A