In general: There are 2n-1 nodes in a full binary tree. By the method of elimination: Full binary trees contain odd number of nodes. So there cannot be full binary trees with 8 or 14 nodes, so rejected. With 13 nodes you can form a complete binary tree but not a full binary tree. So the correct answer is 15.
niraj
Complete Binary tree: -All leaf nodes are found at the tree depth level -All nodes(non-leaf) have two children Strictly Binary tree: -Nodes can have 0 or 2 children
Complete Binary tree: All leaf nodes are found at the tree depth level and All non-leaf nodes have two children. Extended Binary tree: Nodes can have either 0 or 2 children.
A binary tree with n nodes has exactly n+1 null nodes or Null Branches. so answer is 21. MOHAMMAD SAJID
will remain same
The height of a complete binary tree is in terms of log(n) where n is the number of nodes in the tree. The height of a complete binary tree is the maximum number of edges from the root to a leaf, and in a complete binary tree, the number of leaf nodes is equal to the number of internal nodes plus 1. Since the number of leaf nodes in a complete binary tree is equal to 2^h where h is the height of the tree, we can use log2 to find the height of a complete binary tree in terms of the number of nodes.
If N>1, there are (2N-1) - (2N-1-1), otherwise, 1 nodes in the Nth level of a balanced binary tree.
if u assign a 0th level to root of binary tree then,the minimum no. of nodes for depth K is k+1.
binary tree is a specific tree data structure where each node can have at most 2 children nodes. In a general Tree data structure nodes can have infinite children nodes.
12
A full binary tree of depth 3 has at least 4 nodes. That is; 1 root, 2 children and at least 1 grandchild. The maximum is 7 nodes (4 grandchildren).
Same as if two nodes are NOT equal in size. Size of nodes has nothing to do where to insert a new element. The insertion should be applying the search algorithm of that binary tree (so the new inserted element maybe found later). For balanced (in size) binary tree, the above still applied, because 50% of the time the tree is unbalanced (a binary tree with even number of elements is not balanced). Plus, those 2 nodes, may not be the "right" and "left" nodes of a given one, so 2 nodes equals in size has nothing to do with the way the elements being inserted into a binary tree.
Ne=N2+1Here Ne=no. of leaf nodesN2= no. of nodes of degree 2