answersLogoWhite

0


Best Answer

Rt = R1 + R2 That's the formula for the total effective resistance

of two resistors in series.

User Avatar

Wiki User

10y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Were does Rt R1 R2 comes from?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Two wires with resistance R1 and R2 are combined in parallel What will be the equivalent resistance?

If RT is the total resistance, then: 1/RT = (1/R1) + (1/R2)


Are there any cheat codes for madden 09 for PS2?

yes press R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2, then press select to complete the entire game


What is the formula for the series-parallel connection?

/t=/t1=/t2=/t3... vt=v1+v2+v3... rt=r1+r2+r3... series formula....


How do you add resistance in parallel circuit?

the formula is 1/RT = 1/R1 + 1/R2 +.... + 1/Rn RT being total R1 being resistance in first path R2 being resistance in parallel path


What is the code for golden sword?

R1, R1, R2, R2, Right Trigger, Left Trigger, R1, R1, R2, R2.


Is the power dissipated in a parallel circuit larger than the power dissipated in a serial circuit?

Consider t resistors with same Ohmic values. If they are in series total resistance Rt = R1 + R2. if they are in parallel then total resistance Rt = 1/R1 + 1/R2. Series connection will have higher resistance.


How do you beat the whole game cheat?

r1 r2 left left left r1 r1 r2 r2


What is the relation between the total resistance of a parallel connection network of resistors in reference to their single resistance?

The equivalent total resistance of resistors connected in parallel is lower than the resistance of the smallest resistor. The general formula for calculating the total resistance of n resistors in parallel is Rt = 1 / (1/R1 + 1/R2 + ... 1/Rn) For two resistors in parallel, the formula simplifies to Rt = (R1 x R2) / (R1 + R2) If R1 = 10K ohms and R2 = 4.2K ohms, the total resistance of R1 in parallel with R2 is (10,000 x 4,200) / (10,000 + 4,200) = 2957.7 ohms. The total resistance is less than the smallest resistor (4.2K). For three resistors in parallel, the formula is Rt = 1 / (1/R1 + 1/R2 + 1/R3) If R1 = 100 ohms, R2 = 68 ohms, R3 = 1K ohm, the total resistance of these three resistors connected in parallel is: Rt = 1 / (1/100 + 1/68 + 1/1000) = 38.9 ohms The total resistance (38.9 ohms) is lower than the smallest resistor (68 ohms).


Why is double earthing required?

R = r1*r2/r1+r2


How is the total resistance in a parallel circuit is determined?

Series, R1 + R2 +R3 etc,,, Parallel 1/R1+R2+ R3,,,,If you have know resistors. If not just use. E/I x R


The resistance of a 4 ohm resistor and a 12 ohm reisistor connected in series is?

16 ohm, R1 + R2+R3 = RT in series.


What is the formula for finding the Surface Area of a frustum of a cone?

Lateral Surface Area = π(r1 + r2)s = π(r1 + r2)√((r1 - r2)2 + h2)Top Surface Area = πr12Base Surface Area = πr22Total Surface Area = π(r12 + r22 + (r1 * r2) * s) = π[ r12 + r22 + (r1 * r2) * √((r1 - r2)2 + h2) ]