Amount of HCl is 500cm^3 of .8M HCl = .8 x 500/1000 = 0.4 mol. Volume of 10M acid to give 0.4 mol = .4/10 = 0.04dm^3 = 40cm^3 Add 500 - 40 = 460 cm^3 of water. Caution : 10M HCl is highly corrosive and should be handled with care.
CaCO3(s) + 2 HCl(aq) --> CaCl2(aq) + CO2(g) + H2O(l) 500 L * (1.40 mol HCl/1 L HCl) * (1 mol CaCO3/2 mol HCl) * (100.09 g CaCO3/1 mol CaCO3) = 35031.5 g CaCO3 35031.5 g * (1 kg/1000 g) = 35.0315 kg Therefore, about 35.03 kilograms of calcium carbonate is needed to neutralize 500 liters of 1.40 M hydrochloric acid.
For 1 Liter you should take 88.8 mL concentrated HCL (be carefull) and add it to 900 mL water, and finally - after mixing- fill this up to 1000 mL with distilled water. (REMEMBER: ALWAYS ADD ACID TO WATER! -1N in 250 ml : add 22.2 mL to about (or less than) 225 mL water and dilute to final volume = 0.25L
combine 100 mL 6 M HCl with 500 mL H2O
31 g of HCl divided by the molar mass of HCl to find how many mols. HCl --> H(1) + Cl(1) = molar mass of HCl 1.008(1) + 35.45(1)= 36.428 molar mass 31/36.428= 2.97 which is the mols of solute The mols of solute divided by kg of solute = molality 2.97/.500= 1.7 molality
They all produce water, and a type of salts. NaOH + HCL ---> H2O + NaCl KOH + HCl ---> H2O + KCl
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8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
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If you melt the HCl, and it melts at the proper melting point for HCl, then it is a pure substance. If not, it has been mixed with something else, which has altered the purity of the HCl.
This is how you write HCl (Hydrochloric acid) in water: HCl (aqueous) or short form HCl(aq)
The chemical formula (not symbol) of hydrogen chloride is HCl; for a diluted solution you can use "HCl dil." but this isn't a standard formula.