+4 for carbon, -2 for each Sulphur
The oxidation number of sulfur in CS2 is -2. In carbon disulfide (CS2), each carbon atom has an oxidation number of +4, which means the two sulfur atoms must have oxidation numbers that add up to -8 to balance the charge of the molecule. Hence, each sulfur atom has an oxidation number of -2.
To find the number of moles in 19.2 g of CS2, we need to divide the given mass by the molar mass of CS2. The molar mass of CS2 is 76.14 g/mol. So, 19.2 g ÷ 76.14 g/mol ≈ 0.252 moles of CS2.
Following the IUPAC definition method (typically taught in the US) O is with few exceptions -2 , H is +1 in this instance (it is only -1 when linked to a reactive metal). Therefore as the overall oxidation state of the molecule is zero as it is uncharged the oxidation number of C is 0. Other answers are possible as there are other ways to work it out a previous contributor offered this answer:- To get the oxidation number for COH2 can be calculated by adding the oxidation of the individual elements. COH2 C is (+4), 2H is (-2) and O is (-2) which equals to 0.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
The oxidation number of sulfur in CS2 is -2. In carbon disulfide (CS2), each carbon atom has an oxidation number of +4, which means the two sulfur atoms must have oxidation numbers that add up to -8 to balance the charge of the molecule. Hence, each sulfur atom has an oxidation number of -2.
To find the number of moles in 19.2 g of CS2, we need to divide the given mass by the molar mass of CS2. The molar mass of CS2 is 76.14 g/mol. So, 19.2 g ÷ 76.14 g/mol ≈ 0.252 moles of CS2.
For this you need the atomic (molecular) mass of CS2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CS2=76.2 grams10.00 moles CS2 × (76.2 grams) = 762 grams CS2
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
Following the IUPAC definition method (typically taught in the US) O is with few exceptions -2 , H is +1 in this instance (it is only -1 when linked to a reactive metal). Therefore as the overall oxidation state of the molecule is zero as it is uncharged the oxidation number of C is 0. Other answers are possible as there are other ways to work it out a previous contributor offered this answer:- To get the oxidation number for COH2 can be calculated by adding the oxidation of the individual elements. COH2 C is (+4), 2H is (-2) and O is (-2) which equals to 0.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.
Oxidation number of Nb is +4. Oxidation number of O is -2.
MnCl2: oxidation number +2MnO2: oxidation number +4KMnO4: oxidation number +7
The oxidation number for H is +1, and the oxidation number for O is -1.