It is the right arrow: p->fld means (*p).fld
The only "special" operators in C++ are those that cannot be overloaded. That is; the dot member operator (.), pointer to member operator (.*), ternary conditional operator (:?), scope resolution operator (::), sizeof() and typeof().
pointer -> fieldname
There are 5 operators which cannot be overloaded. They are: * .* - class member access operator * :: - scope resolution operator * . - dot operator * ?:: - conditional operator * Sizeof() - operator Note:- This is possible only in C++.
Binary operators require two operands (l-value and r-value) and therefore require two arguments when overloading via external functions. When overloading class member operators, the l-value is the class instance itself (the implicit this pointer), therefore only the r-value need be given as an argument.
The if statementex.if (index < 5)printf("Index is less than 5\n");elseprintf("index is greater or equal to 5\n");(You can also replace the "if" with a "?" and the "else" with a "?" -- no, that would be syntax error)
The only "special" operators in C++ are those that cannot be overloaded. That is; the dot member operator (.), pointer to member operator (.*), ternary conditional operator (:?), scope resolution operator (::), sizeof() and typeof().
Generic pointer of type 'void *' is compatible with any (data-)pointer, but you cannot use the following operators on it: + - ++ -- += -= * -> []
It is a pointer that points to a member of a structure.
On far pointers the comparison operators(== and !=) check the 32 bit value. While >, =,
1. Member-of operator (.) 2. Pointer-to-member-of operator (.*) 3. Ternary condition operator (?:) 4. Scope resolution operator (::) 5. sizeof operator 6. typeid operator
Error message, mainly. The following operations are legal: ptr + integer (pointer) ptr - integer (pointer) ptr - ptr (integer)
A pointer in itself is not an object, because it is not an instance of a class. Of course you can define a class which has only one member, which is a pointer. class Pointer { public void *ptr; }; Pointer p, q, r;
pointer -> fieldname
There are 5 operators which cannot be overloaded. They are: * .* - class member access operator * :: - scope resolution operator * . - dot operator * ?:: - conditional operator * Sizeof() - operator Note:- This is possible only in C++.
Binary operators require two operands (l-value and r-value) and therefore require two arguments when overloading via external functions. When overloading class member operators, the l-value is the class instance itself (the implicit this pointer), therefore only the r-value need be given as an argument.
The if statementex.if (index < 5)printf("Index is less than 5\n");elseprintf("index is greater or equal to 5\n");(You can also replace the "if" with a "?" and the "else" with a "?" -- no, that would be syntax error)
The this pointer can only be used within nonstatic member functions. Friend functions are not members so they have no access to a this pointer. However, you can pass a specific instance of a class to a function via a class reference argument. To understand how friendship works, first understand that a nonstatic member function has the following properties: 1. It has private access to the class. 2. It is scoped to the class. 3. It must be invoked upon an object of the class (has a this pointer). Static member functions have the first two properties while friend functions only have the first property.