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0.02M sulphuric acid= molar mass x M x 1 litre = 98.08 x 0.02 x 1 =1.9616ml/l
1. Add 80mls of distilled water in a beaker. 2. Now add 20mls of concentrated sulphuric acid in small quantities while stirring with a glass rod.
Sulfuric acid must be titrated with a standardized solution of sodium hydroxide.
71.4mL of 1.75 M hydrochloric acid must be diluted with water to prepare 0.500 L of 0.250 M hydrochloric acid.
If water is present it will dilute the sulphuric acid. So if the sulphuric acid has a concentration 1 M , then depending on the volume of water present the concentration will be less than 1M ( < 1M).
0.02M sulphuric acid= molar mass x M x 1 litre = 98.08 x 0.02 x 1 =1.9616ml/l
1. Add 80mls of distilled water in a beaker. 2. Now add 20mls of concentrated sulphuric acid in small quantities while stirring with a glass rod.
Sulfuric acid must be titrated with a standardized solution of sodium hydroxide.
71.4mL of 1.75 M hydrochloric acid must be diluted with water to prepare 0.500 L of 0.250 M hydrochloric acid.
If water is present it will dilute the sulphuric acid. So if the sulphuric acid has a concentration 1 M , then depending on the volume of water present the concentration will be less than 1M ( < 1M).
For preparation of 4N solution of sulphuric acid Dissolve 196 gm H2SO4 in 1000 ml DM water. Calculation N E V Weight = ------------ 1000 Where N= Normality E= Equivalent weight V= Volume
M. Rahmani has written: 'Hydrodynamic modeling of corrosion of carbon steels and cast irons in sulfuric acid' -- subject(s): Carbon steel, Cast-iron, Corrosion, Corrosion and anti-corrosives, Sulphuric acid, Testing
This depends on your experiment.
preparation of m-nitro benzoic acid from benzene
You'll need to know two things: what is the concentration of butyric acid you are starting with and how much 1 M butyric acid you want to end up with. From this, you can calculate how much water you need to add to a given volume of concentrated butyric acid to make 1 M butyric acid.
It depends on what yo start with. If you start with concentrated sulfuric acid, it is usually about 18 M or 36 N. So, you would dilute it approximately 1:36 or 1 ml diluted up to 36 mls or any multiple of that. To get the exact dilution, you need to know the exact molarity. If you have some other molarity acid, then the calculations would vary accordingly.
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