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we use kcl to find out current with the help of equation ;and also we calculate the value of voltage ,kcl is the law which explaine that all the leaving current =entering current or sum of all currents at junction is zero
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∙ 14y ago
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What is the mole ratio for KCl?
KCl
What volume of 0.060 M KCl solution contains 2.39g of KCl?
MW KCl = 74.6 g/mol2.39 gKCl * (1 mol KCL/74.6 g KCl)*(1 L solution/0.06 mol KCL) = 0.534 L
How many grams of KCl are needed to prepare 125 mL of a 0.720 M KCl solution?
The answer is 6,71 g dried KCl.
How is the bond in F2 different from the bond in KCl?
F2 is covalent and KCl is ionic
Is KCL ionic 1 or ionic 2?
KCl is an ionic bond type I
How many moles of KCl are contained in 0.635L of 2.2M KCl?
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
What is the mole ratio for KCl?
KCl
What is KCl?
KCL is Potassium Chloride.
How many ml of 0.25M KCl are needed to provide 0.012 moles of KCl?
0.012mol KCl x (1L/0.25mol KCl) x (1000ml/1L) = 48 mL KCl
How many moles of KCl are contained in 1.7L of a 0.83M KCl solution?
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
What volume of 0.060 M KCl solution contains 2.39g of KCl?
MW KCl = 74.6 g/mol2.39 gKCl * (1 mol KCL/74.6 g KCl)*(1 L solution/0.06 mol KCL) = 0.534 L
What is the compound for KCl?
I'm guessing you meant KCl or potassium chloride.
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
What is the solubility of KCl in DMF?
KCl is soluble in DMF
Is KCl an element or compound?
KCl is a compound not an element.
How much 75.66MKCL is required toprepare 1L of solution?
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!
Is KCl insoluble?
No. Potassium chloride (KCl) is soluble in water.
