NaOH is a strong base.It helps in the manufacture of NaCl that is the salt we used in day to day life.
Sodium hydroxide is a strong base, corrosive, dangerous - causing burnings on the skin.
NaOH is between the most used substances in the chemical industry.
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
NaOH --> Na+ and OH-
This solution contain 26,3 g NaOH.
it is a base
The premise of this question is incorrect. When NaOH is added to water the hydroxide concentration increases. NaOH is a base. If a substance decreases hydroxide concentration it would be an acid.
3.42 moles NaOH (39.998 grams/1 mole NaOH) = 137 grams NaOH
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
208g NaOH
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
No, NaOH is a compound
NaOH and HCl
Determine the number of moles 15.5 g NaOH 15.5 g NaOH x (1 mole NaOH/39.9971 grams NaOH) = 0.388 moles NaOH Molarity = moles NaOH/L solution 0.540 M = 0.388 moles NaOH/L soln L soln = 0.718 L --> A
Alcohols react with NaOH, as ethanol forms sodium ethoxide with NaOH.
Hi, 6N NaOH = 6M NaOH 6M NaOH are 6 moles in 1L Mw (NaOH) = 39.88 gr/mole so: m = n x MW = 6 x 39.88 = 239.28 gr NaOH. :)