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What current will be needed to produce a voltage of 5V cross a 12kΩ resistor?
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What value of resistor will be needed to produce the current of 100mA when a voltage of 12V is applied across the resistor?
R = E/I = (12)/(0.1) = 120 ohms(Make it a big one. It dissipates I2R = 0.01 x 120 = 1.2 watts.)
What size resistor needed to drop 3 volts dc to 2.5 volts dc?
You will need to take the resistance of the load into account if you are going to design a voltage divider. The resistance of the load can completely change the voltage ratio of a voltage divider if not factored into the calculation. you can measure or read R(load), then R(needed) = 0.8 R(load)
If a circuit has a resistance of 4 ohm's how much voltage is needed to produce a 1.4 current in the circuit?
Voltage across a resistance = (resistance) x (current through the resistance) =4 x 1.4 = 5.6If the ' 1.4 ' is Amperes of current, then the required voltage is 5.6 volts.
What is a series circuit that is used to produce a voltage source of desired magnitude from a higher voltage battery?
Such a circuit would be called a voltage divider.The circuit would consist of two or more resistors in series across a battery or other voltage source. Each resistor would drop a certain amount of voltage (proportional to its resistance), and by considering the voltage drops, the investigator could pick two points in the circuit from which to take (or "pick off") the desired voltage needed for a project. Let's look at just one example.If a 12 volt battery has two 1K ohm resistors in series across it, each resistor will drop 6 volts. By connecting wires from each end of one resistor, the 6 volts can be "picked off" and used to do something else. Certainly there are limitations concerning how much current can be drawn from the circuit (called loading the circuit), as the "diversion" of current around the resistor that is providing the voltage will change the voltage that is being picked off. But for small amounts of current, the voltage divider will work adequately.
How much voltage is needed to produce a current of 0.5 ampere in a circuit that has a resistance of 24 ohms?
Work it out yourself -the equation is: voltage = current x resistance.
What current will be needed to produce a voltage of 5V across a 12kΩ resistor?
Ohm's Law: Current = voltage divided by resistance. 5 V divided by 12 KΩ is 416 2/3 ma
What value of resistor will be needed to produce the current of 100mA when a voltage of 12V is applied across the resistor?
R = E/I = (12)/(0.1) = 120 ohms(Make it a big one. It dissipates I2R = 0.01 x 120 = 1.2 watts.)
How much voltage is needed to produce a current of 2 ampsthrough a resistance of 6 ohms?
12 voltage
What voltage is needed to produce 6 A current through a resistance of 3?
18volts
The voltage needed to produce a current of 8 A in a resistance of 12 ohms is?
8x12=96
What voltage is needed to produce a 6 A current in an object that has a resistance of 3 ohm?
18 volts
What size resistor is needed to drop 24 volts dc to 12volts dc?
Its dependent what will by rated power of the device (current).
What happens to the current flowing through a metal resistor when the voltage across is increased?
When the voltage is increased across a metal film resistor, the current flow will also increase. Ohm's law states that the current flowing through a resistor is directly proportional to the voltage across that resistor. I = V/R Let us assume an initial voltage drop across a 4.99K ohm metal film resistor is 5V. The current flow through the resistor is calculated to be: I = 5/4990 = 0.001 Amps or 1 mA If that voltage were to say double to 10V: I = 10/4990 = 0.002 Amps or 2 mA Using these values it is also possible to calculate the power dissipated by the resistor. P = I*V = 0.002 * 10 = 0.02 Watts This power calculation determines the minimum physical case size needed for the resistor to function within these conditions. Anything smaller, the resistor will fail.
What size resistor needed to drop 3 volts dc to 2.5 volts dc?
You will need to take the resistance of the load into account if you are going to design a voltage divider. The resistance of the load can completely change the voltage ratio of a voltage divider if not factored into the calculation. you can measure or read R(load), then R(needed) = 0.8 R(load)
If a circuit has a resistance of 4 ohm's how much voltage is needed to produce a 1.4 current in the circuit?
Voltage across a resistance = (resistance) x (current through the resistance) =4 x 1.4 = 5.6If the ' 1.4 ' is Amperes of current, then the required voltage is 5.6 volts.
What is a series circuit that is used to produce a voltage source of desired magnitude from a higher voltage battery?
Such a circuit would be called a voltage divider.The circuit would consist of two or more resistors in series across a battery or other voltage source. Each resistor would drop a certain amount of voltage (proportional to its resistance), and by considering the voltage drops, the investigator could pick two points in the circuit from which to take (or "pick off") the desired voltage needed for a project. Let's look at just one example.If a 12 volt battery has two 1K ohm resistors in series across it, each resistor will drop 6 volts. By connecting wires from each end of one resistor, the 6 volts can be "picked off" and used to do something else. Certainly there are limitations concerning how much current can be drawn from the circuit (called loading the circuit), as the "diversion" of current around the resistor that is providing the voltage will change the voltage that is being picked off. But for small amounts of current, the voltage divider will work adequately.
What size resistor is needed when wiring two leds in parallel using 6 volts dc?
A: LEDS are devices that needs a certain voltage and current typically 1.8 and 20 ma
