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Five water molecules.
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How many grams of copper sulfate pentahydrate CuSO4 5H2O would you heat to produce 29.8 g of water?
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
What is a balanced equation for the decomposition of copper sulfate pentahydrate?
CuSO4•5H2O + heat ---> CuSO4 + 5H2O
How many grams of copper sulfate would you heat to produce 29.8g of water?
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
Is the percent by mass of copper in CuSO4 5H2O the same as in CuSO4?
No. The % of Cu by mass in CuSO4 will be greater than the % of Cu by mass in the pentahydrate (5H2O) because in the hydrate there is added mass (5 H2O = 90 g) but no added Cu.
What is the equation for copper II chloride hexahydrate?
Cu(NO3)2 x 5H2O is the chemical formula for copper II nitrate pentahydrate.
What is the Empiracal formula for cupric sulfate pentahydrate?
CuSO4•5H2O
What is the chemical formula of cupric bi sulfate?
CuSO4 5H2O
What is the balanced equation for copper sulphate pentahydrate?
CuSO4 * 5H2O
The equation for the dehydration of CuSO4 5H2O heat?
their isn't one CuSO4 is an anhydrous salt which will absorb water so the way to find out how much is in it is to find out the difference in water befor and after addition and calculate it by finding the mols of water absorbed incomplarison with the number of mols of CuSO4 used. it is normally wrighten nH2O. CuSO4
What is the formula for hydrated copper II sulfate?
Copper sulfatepentahydrate is a solid at 20 degrees Celsius has a density of 2.28g/cm3 (cubed)... and its' chemical symbol is CuSO4-5H2O
What is the molecular for of Na2S2O3-5H2O?
The molecular mass of sodium thiosulfate heptahydrate is 248,18 g.
What is the balanced equation for borax and hydrochloric acid?
Na2B4O7.10H2O + 2HCl --> 4H3BO3 + 2NaCl + 5H2O
