7.4 moles iron (55.85 grams/1 mole Fe)
= 413.29 grams iron
1 mole of iron weighs
48 percent of 74 is 35.52, so there are 35.52 grams of salt. The molar mass of salt (NaCl) is 58.443 grams per mole, giving .608 moles of salt.
The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )
The molar mass of any compound contain a number of molecules equal to the number of Avogadro:6,022 140 857(74).10e+23.
1 mole of mass of ca (OH) 2 = 40*1 + (16 + 1) 2 = 40 + 34 = 74g. So, mass of 24 moles = 24*74 = 1776g.
protons= 74 neutrons= 110 electrons= 74
48 percent of 74 is 35.52, so there are 35.52 grams of salt. The molar mass of salt (NaCl) is 58.443 grams per mole, giving .608 moles of salt.
2.61 ounces.
74,000 grams1 kg = 1000 grams74 kg = 74 kg * 1000 grams/1 kg = 74,000 grams
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )
Potato may weigh anything between 100 to 110 grams or less depending on the size of the vegetable as a singular unit. Single potato can weigh up to 400 to 500 grams each. 74 to 75 % of the content of a potato is water and it is a good source of carbohydrates which measure up to 22.6 grams in each 100 grams of potato.
74 grams of water is equal to 74 milliliters of water. These type of conversions are the easiest to complete since they will always be equal to one another.
There are 1000 grams in one kilogram. Therefore, 7.4 grams is equal to 7.4/1000 = 0.0074 kilograms.
1 mole
A 74 inch sturgeon would weigh about 126 pounds.
74 litres of water weighs 74 Kilograms - about 162 pounds.
Move the decimal two places to the left. 74 cg= .74 g