Cu(NO3)2 and H2 are formed
Cu + HNO3 = Cu(NO3)2 + NO + H2O
To find the volume of 16M HNO3 required to react with 0.0214g of Cu metal, you need to calculate the moles of Cu. Then, using the balanced equation for the reaction between Cu and HNO3 (Cu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O), you can determine the moles of HNO3 needed. Finally, using the molarity of the HNO3 solution, you can calculate the volume in drops.
The balanced chemical equation for the reaction between copper (Cu) and nitric acid (HNO3) is Cu + 4HNO3 -> Cu(NO3)2 + 2NO2 + 2H2O. From the equation, it can be seen that 1 mol of Cu reacts with 4 mol of HNO3. Therefore, to react with 2.0 mol of HNO3, 0.5 mol of Cu is needed. The molar mass of Cu is approximately 63.5 g/mol, so 0.5 mol of Cu would be equivalent to 31.75 grams.
The balanced chemical equation for the reaction between copper (Cu) and nitric acid (HNO3) is: 3Cu + 8HNO3 -> 3Cu(NO3)2 + 2NO + 4H2O According to the equation, 8 moles of HNO3 are required to react with 3 moles of Cu. Therefore, to react with 6 moles of Cu, you would need 16 moles of HNO3.
Cu + 4HNO3 ----->Cu(NO3)2 + 2NO2 + 2H20
The reaction is:Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O
no reaction because Cu is below Zn at electrochemical series ,so Cu can't take Zn away from its salts
600 (cu centimeters) = 36.6142465 cu inches
Copper (I)+ nitric acid > Copper (II) Nitrate + nitric dioxide + water Cu(s) + HNO3 (aq) > Cu(NO3)2(s) + NO2(g) + H2O(l) Balanced equation: Cu(s) + 4HNO3 (aq) > Cu(NO3)2(s) + 2NO2(g) + 2H2O(l)
The chemical equation for the reaction between copper carbonate (CuCO3) and nitric acid (HNO3) is: CuCO3 + 2HNO3 → Cu(NO3)2 + CO2 + H2O. This reaction produces copper(II) nitrate, carbon dioxide, and water.
No. In concentrated nitric acid, the reaction produces copper (II) nitrate, nitrogen dioxide (a toxic, brownish colored gas) and water. The reaction is as follows: Cu(s) + 4HNO3(aq) --> Cu(NO3)2(aq) + 2NO(g) + 2H2O(l) In diluted nitric acid, the reaction produces copper (II) nitrate, nitric oxide (NO), and water. The reaction is as follows: 3Cu(s) + 8HNO3(aq) --> 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(l) (Source: www.angelo.edu)
To determine the number of moles of HNO3 present in 450 g, we first need to calculate the molar mass of HNO3, which is approximately 63.01 g/mol. Next, we use the formula moles = mass/molar mass to find the number of moles. Therefore, 450 g of HNO3 is equal to 7.14 moles of HNO3.