This reaction doesn't exist.
The balanced equation for Na + HNO3 is: 2Na + 2HNO3 -> 2NaNO3 + H2
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
The chemical equation is:Sn + 4 HNO3 = SnO2 + 4 NO2 + 2 H2O
To balance the equation N2O5 + H2O → 2HNO3, start by counting the number of atoms for each element on both sides of the equation. Then adjust the coefficients in front of each compound to balance the equation. In this case, you need to put a coefficient of 2 in front of HNO3 on the product side to balance the nitrogens and oxygens.
I think that should be 2N2O4+2H2O+O2 --> 4HNO3 But i'm not sure
KOH + HNO3 --> KNO3 + H2O -------------------------------------site mis-correcting again. All letters capitalized.
No. In concentrated nitric acid, the reaction produces copper (II) nitrate, nitrogen dioxide (a toxic, brownish colored gas) and water. The reaction is as follows: Cu(s) + 4HNO3(aq) --> Cu(NO3)2(aq) + 2NO(g) + 2H2O(l) In diluted nitric acid, the reaction produces copper (II) nitrate, nitric oxide (NO), and water. The reaction is as follows: 3Cu(s) + 8HNO3(aq) --> 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(l) (Source: www.angelo.edu)
This is a redox reaction where NO2 is oxidized to HNO3 and H2O is reduced to NO. To balance the equation, start by balancing the atoms of each element (N, O, and H) on both sides of the reaction. Then, add electrons to balance the charges. The balanced equation is: 3NO2 + H2O -> 2HNO3 + 2NO + 2H+.
The balanced equation for the reaction between HNO3 and NaHCO3 is: 2 HNO3 + NaHCO3 → NaNO3 + H2O + CO2
299 H2SO4 + 10 K4Fe(CN)6 + 122 KMnO4 = 60 CO2 + 5 Fe2(SO4)3 + 188 H2O + 60 HNO3 + 162 KHSO4 + 122MnSO4
Cu + HNO3 = Cu(NO3)2 + NO + H2O
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.