No. In concentrated nitric acid, the reaction produces copper (II) nitrate, nitrogen dioxide (a toxic, brownish colored gas) and water. The reaction is as follows:
Cu(s) + 4HNO3(aq) --> Cu(NO3)2(aq) + 2NO(g) + 2H2O(l)
In diluted nitric acid, the reaction produces copper (II) nitrate, nitric oxide (NO), and water. The reaction is as follows:
3Cu(s) + 8HNO3(aq) --> 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(l)
(Source: www.angelo.edu)
The chemical equation is:Sn + 4 HNO3 = SnO2 + 4 NO2 + 2 H2O
This is a redox reaction where NO2 is oxidized to HNO3 and H2O is reduced to NO. To balance the equation, start by balancing the atoms of each element (N, O, and H) on both sides of the reaction. Then, add electrons to balance the charges. The balanced equation is: 3NO2 + H2O -> 2HNO3 + 2NO + 2H+.
KOH + HNO3 --> KNO3 + H2O -------------------------------------site mis-correcting again. All letters capitalized.
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
299 H2SO4 + 10 K4Fe(CN)6 + 122 KMnO4 = 60 CO2 + 5 Fe2(SO4)3 + 188 H2O + 60 HNO3 + 162 KHSO4 + 122MnSO4
The chemical equation is:Sn + 4 HNO3 = SnO2 + 4 NO2 + 2 H2O
This is a redox reaction where NO2 is oxidized to HNO3 and H2O is reduced to NO. To balance the equation, start by balancing the atoms of each element (N, O, and H) on both sides of the reaction. Then, add electrons to balance the charges. The balanced equation is: 3NO2 + H2O -> 2HNO3 + 2NO + 2H+.
KOH + HNO3 --> KNO3 + H2O -------------------------------------site mis-correcting again. All letters capitalized.
I think that should be 2N2O4+2H2O+O2 --> 4HNO3 But i'm not sure
The balanced equation for the reaction between HNO3 and NaHCO3 is: 2 HNO3 + NaHCO3 → NaNO3 + H2O + CO2
Cu + HNO3 = Cu(NO3)2 + NO + H2O
This reaction is:S + 6 HNO3 = H2SO4 + 2 H2O + 6 NO2
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
299 H2SO4 + 10 K4Fe(CN)6 + 122 KMnO4 = 60 CO2 + 5 Fe2(SO4)3 + 188 H2O + 60 HNO3 + 162 KHSO4 + 122MnSO4
The acid-base reaction between nitric acid (HNO3) and sodium hydroxide (NaOH) produces sodium nitrate (NaNO3) and water (H2O). The balanced chemical equation for this reaction is: HNO3 + NaOH → NaNO3 + H2O.
The reaction you provided is the dissociation of nitric acid (HNO3) in water. In this reaction, HNO3 donates a proton to water, forming hydronium ions (H3O+) and nitrate ions (NO3-), indicating that HNO3 is an acid.
The conjugate base for the equation HNO3 + NaOH -> H2O + NaNO3 is the nitrate ion (NO3-), which is formed when the strong acid HNO3 donates a proton to water (H2O) to form the weak conjugate base NO3-.