This yields a light sensitive AgCl precipitate
the above answer is not possible since there is no Silver (Ag) in either HNO3 or NaCl
Sodium chloride doesn't react with nitric acid.
The theoretical yield of HNO3 is the maximum amount of nitric acid that can be produced in a chemical reaction based on stoichiometry and assuming 100% yield. It can be calculated by converting the given amount of reactant to moles, using the balanced equation, and then converting moles to mass of HNO3.
Neutralization: HNO3 + NaOH -> NaNO3 + H2O Decomposition by heating: NaNO3 -> NaNO2 + 1/2 O2 Preparation of HNO2: NaNO2 + HCl -> HNO2 + NaCl
Ammonia and nitric acid react to form ammonium nitrate. NH3 + HNO3 --> NH4NO3
2HNO3 + Ca(OH)2 ==> 2H2O + Ca(NO3)2
This yields nitric and nitous acid (1 to 1) H2O + 2 NO2 --> HNO2 + HNO3
NaCl is extracted three times rather than one time to ensure that the maximum amount of NaCl is extracted from the mixture.
Potassium hydroxide and nitric acid will yield potassium nitrate and water. KOH + HNO3 --> H2O + KNO3
Percentage yield is given as:-%yield = (mass of product obtained experimentally/theoretical yield)x100where the theoretical yield is the maximum mass which could possibly be obtained assuming 100% stoichiometry.So, say as an example if you start with 71g of Cl2 then:-mol = mass/Mr Mr of Cl2 = 71mol = 71/71mol = 1 of Cl2This is the limiting reagent, assuming we have at least 46g of sodium, thus we double this number as the reaction is 1:21 mole Cl2---->2moles NaClagain we use:-mole = mass/Mr Mr of NaCl = 58.52 x Mr = mass2 x 58.5 = massmaximum mass of NaCl possible = 117gIf the reaction is carried out and we achieve 100g of NaCl then:-%yield = (100/117) x 100= 85.5%
HNO3 is nitric acid.
HNO3 is Nitric Acid
All acids yield a proton and a anion. For eg: HCl -------> H+ + Cl- H2SO4 --------> H+ + SO42-HNO3 ---------> H+ + NO3-
1 mg/l = 1ppm1 g/l = 1000 ppmNaCl ----------------> Na+ + Cl-58.5 g NaCl gives 22.989 g Na+(58.5 / 22.989) = 2.545 g of NaCl is required to give 1 g of Na+When 2.545 g of NaCl is dissolved in 1 liter water will yield 1000 ppm of Na+ in NaCl solution.