SO2 is an acidic compound, while NH3 is a basic compound. So, what you should expect is a neutralization reaction. The reaction is:
SO2 + 2NH3 + H2O -----> (NH4)2SO3
SrO, LiI, NH4Cl
Ammonia + Hydrochloric acid ----> Ammonium Chloride NH3 + HCl ----> NH4Cl
A white solid Ammonium chloride is formed, HCl + NH3 -----> NH4Cl
1.75 moles SO2 x 6.02x10^23 molecules SO2/mole SO2 = 1.05x10^24 molecules
SO2 is Sulphut Dioxide.
SO2 is the heaviest
Sulfur dioxide SO2 (written with two capitals)
nonmetals. Examples include H2O, SO2, NH3.
SrO, LiI, NH4Cl
Yes I did it and nothing happend
Yes, all the solutions, elements and compounds are homogeneous Alcohol-Water , Lemonade , Oxygen, Nitrogen, Coke, CO2, SO2, H2SO4, NH3, CH3COOH.....
1 mole SO2 = 64.064g SO2 0.45g SO2 x 1mol SO2/64.064g SO2 = 0.0070 mole SO2
A refreshing drink as a solution is prepared.
Ammonia + Hydrochloric acid ----> Ammonium Chloride NH3 + HCl ----> NH4Cl
A white solid Ammonium chloride is formed, HCl + NH3 -----> NH4Cl
The asker added, "I am looking to destroy SO2 accumulation in a gas system". In my opinion, you'd be likely to get a reaction between the ammonia (NH3) and the peroxide (H2O2). I'm not sure whether the sulfur dioxide (SO2) would be preferentially affected by the peroxide, but if it were, you'd likely get sulfur trioxide (SO3), which dissolves in H2O to produce H2SO4 -- sulfuric acid. As for a reaction between the peroxide and the ammonia -- based on limited experience, I believe there are several possibilities, and that the products you got would be dependent upon temperatures.
1.75 moles SO2 x 6.02x10^23 molecules SO2/mole SO2 = 1.05x10^24 molecules