Nothing. All the light bulbs in your house are connected in parallel. In a parallel circuit the same voltage appears across all the loads, and the supply voltage is nearly constant, so if one bulb is switched off it makes no difference to the others.
That bulb goes out. The other bulbs remain on.
it should become dimmer
The whole circuit fails - because the action of the bulb blowing cuts the circuit.
Yes but very slightly,because temperature coefficient of bulb element is very low.
It will all just turn off. Because with a series circuit the power travels through each light bulb in a series (one after another) so if it is interrupted by there being a burned out or removed bulb, the circuit will not be complete and thus not work at all. If you want to see for yourself, most Christmas lights are series circuits, go ahead and take one out.
48 ohms
in a series circuit current flows through each resistor or light bulb and if one item burns out the complete circuit goes dead such were the old fashioned xmas tree lights. They were wire in series and if one light burned out you had to test each light bulb til you found the one burned out to get the whole string to work again. In a parallel circuit each resistor, motor, light bulb has its own ground so if you lost one light in a circuit the rest of them continue to burn.
A circuit is complete
each buld has different parrel lines so on i on bulb isn't working the other bulb will be effected because it have different parrell to the swich.b thank i am going to kill you james leglat because you suck.
The bulb becomes brighter unless it is too much till it shot-circuits.
because when u put the fuse u creat a circut enabeling power to get to the bulb the fuse is classed as circut breaker
the bulb is burnt out or the circut board is faulty. The circut board is a common failure in the older versions and was a safety warrant recall.
The glass of the light bulb is not conductive, so the circuit would not be completed. You would need to join the wires to the positive and negative contacts on the base of the bulb for the circuit to work.
Yes. A typical light bulb socket is an open circuit when the bulb is removed, thus blocking the flow of current and turning off the remaining bulb. The removed bulb would go out too, of course. It is possible to imagine a bulb socket that reverts to a closed circuit when the bulb is removed. In that case, the remaining bulb would remain lit.
Because circuit don't break unlike in series.That means rest of the component are getting the voltage across them.
Hi there, I also have a test coming up. The only thing I can think of is inputs! Sorry :( :(
when a light bulb is switched on it will blown..............