the electrical potential is also increased;electricity does not travel through wire but around the outside,which is why transmission lines are bare
The electric field strength would weaken. :)
It will be pushed away from the source of the electric field.
First off you know that when it says "Proton" you should know that its a Positive (+) Charged subatomic particle! Now You use the equation that says --> Volt = Electric Potential Energy / Q Volt = 0.5 / +1 (proton) Volt = 0.5
The magnitude of the electric field is 2.5.
in an electric field
Zero Dipole would set itself such that dipole moment vector is along the electric field vector
Electric field intensity is related to electric potential by the equation E = -dV/dx, where E is the electric field intensity, V is the electric potential, and x is the distance in the direction of the field. Essentially, the electric field points in the direction of decreasing potential, and the magnitude of the field is related to the rate at which the potential changes.
THIS IS A GOOD QUESTION IF WE PLACE THE CHARGE IN THE ELECTRIC FIELD AT A DISTANCE R FROM THE ELECTRIC FIELD AND PLACED THE ANOTHER POINT CHARGE AT A ANOTHER DISTANCE r WHERE R IS GRATER THAN THE SMALL R THEN THE ELECTRIC FIELD AT r IS MORE THAN THE ELECTRIC FIELD AT POINT R.ORWE CAN SAY THAT IF THE CHARGE IS PLACED IN THE DIRECTION OF ELECTRIC FIELD THAN ITS ELECTROSTATIC POTENTIAL ENERGY WILL DECREASE OR WHEN IN DIRECTION OPPOSITE THAN VICEVERSA
no electric field is not a potential field .ELECTRIC FIELD IS A SCALAR QUANTITY WHERE AS POTENTIAL IS THE VECTOR QUANTITY. NO SCALAR QUANTITY HAS A FIELD SO THERE IS NO RELATION BETWEEN ELECTRIC FIELD AND POTENTIAL OR IN OTHER WORD POTENTIAL HAS NO FIELD <<>> An electric field is a vector field, because it has magnitude and direction. A pair of charged parallel plates has an electric field between them directed from the negative to the positive plate. The electric field is the gradient of the potential, which is another field but a scalar one. A field is just a quantity with a value that depends on positon. The potential is measured in volts and if one plate is grounded and the other at positive potential V, the potential rises from zero to V as the position changes from the lower plate to the top one.
If the electric field is zero, the electric potential is a constant value, but it does not tell you what that value is. All the electric field tells you is how the electric potential changes within the region you are looking at. If the electric potential at one end of a cylindrical region is 7 V and the electric field is zero within the whole cylinder, then the electric potential is 7 V at the other end, or somewhere in the middle, or on the side, and so forth. An electric field of zero tells you the potential does not change, but doesn't say anything about what it is outside of the region you're looking at.
The magnitude of the electric potential is dependent upon the particle's charge and the electric field strength.
The potential gradient gives the electric field intensity E at point in electric field which is directed from high to low potential. An electron being a negative charge particle therefore will tend to move from low potential to high potential, hence will move up the electric field
This is because potential decreases if we move further from a positive plate
The potential gradient gives the electric field intensity E at point in electric field which is directed from high to low potential. An electron being a negative charge particle therefore will tend to move from low potential to high potential, hence will move up the electric field
any gadget won't work, as no current would be able to pass due to lack of electric potential difference
The potential difference. The electrons flows from a lower potential to a higher potential. The electric current flows in the opposite direction. The electric field's direction is always from a higher potential to a lower potential. Its kind of like a waterfall. The water always falls down not up. It goes from a higher potential to a lower potential.
An electric field gets stronger the closer you get to a charge exerting that field. Distance and field strength are inversely proportional. When distance is increased, field strength decreases. The opposite is true as well. Additionally, field strength varies as the inverse square of the distance between the charge and the observer. Double the distance and you will find that there is 1/22 or 1/4th the electric field strength as there was at the start of your experiment.
The strength of the electric field approaches zero