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Assuming butane undergoes complete combustion in 1 mole of oxygen, 8/13 moles of carbon dioxide and 10/13 moles of water are formed.
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Why does a butane gas lighter register carbon monoxide reading when expose to a gas detector?
Incomplete combustion of the butane. Which means that there is a lack of oxygen getting into the system. C4H10 + 4½O2 -> 4CO + 5H2O In excess O2 only CO2 and H2O are produced. C4H10 + 6½O2 -> 4CO2 + 5H2O
Try balancing the equations for the reactions in which propane (C3H8) and butane (C4H10) are burned in oxygen to form carbon dioxide and water.?
Burning of propane:CH3H8 + 5 O2 = 3 CO2 + H2OBurning of butane:2 CH4H10 + 13 O2 = 8 CO2 + 10 H2O
When H2 and O2 react to form water what happens to the atoms that were gas?
h2 is water because when divide by 2 equals into 5 so i am very handsome
H2 plus O2 equals H2O If you have 1.42 moles of hydrogen how many moles of oxygen will react with it?
Balanced equation first. 2H2 + O2 >> 2H2O 1.42 mol H2 ( 1mol O2/2mol H2 ) = 0.71mol O2 to react with H2
Is the mass of 1mole of O and 1 mole of S same?
No; 1 mole of molcular oxygen (O2) is 31,998 g and 1 mole of sulfur (S) is 32,06 g.
What happens if you mix h202 with baking soda?
They will react together. will form O2 and H2O as results.
24g of CH4 react with 96 g of O2?
CH4 + 2O2 gives CO2 and 2H2O.So 16g of CH4 react with 64g of O2.So 24g react with 96g of O2
How do metals react with o2?
how do metals react with oxygen
What is a chemical equation that accurately represents what happens when sulfur and oxygen react to form sulfur trioxide?
2so2 + o2 ----> 2so3
Why does a butane gas lighter register carbon monoxide reading when expose to a gas detector?
Incomplete combustion of the butane. Which means that there is a lack of oxygen getting into the system. C4H10 + 4½O2 -> 4CO + 5H2O In excess O2 only CO2 and H2O are produced. C4H10 + 6½O2 -> 4CO2 + 5H2O
What happens when sulphurdioxide is dissolved in water?
They react to form sulphuric acid. 2 SO2 + 2 H2O + O2 → 2 H2SO4
How do you ensure that all the Mg would react completely with O2?
First you must find out what mass of each would react perfectly, then, if you have more than is needed of one of the reactants (if it is in excess) all of the reactant will react. Here is the calculation you need, for example, say you have 50g of each reactant. Step 1-Write out formula of reactants Mg + O2 = MgO2 1mole 1 mole Step 2 - Find the gram formula mass of reactants 1 mole Mg= 24.3 g 1 mole O2= 32 g 24.3g Mg reacts with 32g O2 Step 3 - Find amount required to react 50g Mg -- 50/32x24.3 =37.9 =37.9g Mg From that we can see that since there is 37.5g Mg and only 24.3g is needed to react completely with O2, the Mg is in excess. Substitute your starting weights in there and use that calculation, and add more than the required amount, that way you can be sure.
What happens when CH3CH2OH and O2 react?
It is ethanol, normal alcohol, it burns with oxygen from air.The balanced reaction equation is:CH3CH2OH + 3 O2 --> 2 CO2 + 3 H2O
Try balancing the equations for the reactions in which propane (C3H8) and butane (C4H10) are burned in oxygen to form carbon dioxide and water.?
Burning of propane:CH3H8 + 5 O2 = 3 CO2 + H2OBurning of butane:2 CH4H10 + 13 O2 = 8 CO2 + 10 H2O
Assuming no change in temperature and pressure calculate the volume of O2 in liters required for the complete combustion of 14.9 L of butane C4H10?
Assuming no change in temperature and pressure, calculate the volume of O2 (in liters) required for the complete combustion of 14.9 L of butane (C4H10):
What volume of O2 at stp is necessary to react with o200 moles of SO2 to form SO3?
2.24 L O2 (= 0.100 mol O2) is needed to react with 0.200 moles of SO2 to form SO3
When H2 and O2 react to form water what happens to the atoms that were gas?
h2 is water because when divide by 2 equals into 5 so i am very handsome
